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7nadin3 [17]
3 years ago
10

I don’t understand. online school is hard

Mathematics
2 answers:
WARRIOR [948]3 years ago
8 0

Answer:

online is harder than

Step-by-step explanation:

school is nice place

ZanzabumX [31]3 years ago
8 0
Online school is retarted
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Write the standard form of the equation of the circle that passes through the point
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Answer:

The standard form of the equation of the circle is x^2+y^2=1.

Step-by-step explanation:

A circle is the set of points in a plane that lie a fixed distance, called the radius, from any point, called the center.

The equation of a circle in standard form is

                                             (x-h)^2+(y-k)^2=r^2

where <em>r</em> is the radius of the circle,  and <em>h</em>, <em>k</em> are the coordinates of its center.

When the center of the circle coincides with the origin h=k=0, so

                                            (x-0)^2+(y-0)^2=r^2\\x^2+y^2=r^2

We are also told that the circle contains the point  (0, 1), so we will use that information to find the radius <em>r</em>.

                                                   0^2+1^2=r^2\\r^2=0^2+1^2\\r^2=1\\r=\sqrt{1}

Therefore, the standard form of the equation of the circle is x^2+y^2=1.

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Hello, Here is a link to the answer. I am posting this link because it is a Brainly link and a verified answer brainly.com/question/219158
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