It’s so sis is not a or b it’s c
Answer:
Volume = 16 unit^3
Step-by-step explanation:
Given:
- Solid lies between planes x = 0 and x = 4.
- The diagonals rum from curves y = sqrt(x) to y = -sqrt(x)
Find:
Determine the Volume bounded.
Solution:
- First we will find the projected area of the solid on the x = 0 plane.
A(x) = 0.5*(diagonal)^2
- Since the diagonal run from y = sqrt(x) to y = -sqrt(x). We have,
A(x) = 0.5*(sqrt(x) + sqrt(x) )^2
A(x) = 0.5*(4x) = 2x
- Using the Area we will integrate int the direction of x from 0 to 4 too get the volume of the solid:
V = integral(A(x)).dx
V = integral(2*x).dx
V = x^2
- Evaluate limits 0 < x < 4:
V= 16 - 0 = 16 unit^3
Answer:
cubic polynomial
Step-by-step explanation:
Given polynomial is ![\[h(x)=-6x^{3}+2x-5\]](https://tex.z-dn.net/?f=%5C%5Bh%28x%29%3D-6x%5E%7B3%7D%2B2x-5%5C%5D)
A polynomial of degree 1 is a linear polynomial.
A polynomial of degree 2 is a quadratic polynomial.
A polynomial of degree 3 is a cubic polynomial.
In this case the exponent with the maximum value in the polynomial is 3.
Hence the degree of the polynomial h(x) is 3.
Hence the given polynomial is a cubic polynomial.
Answer:
14x
Step-by-step explanation:
please mark this answer as the brainlest
Answer:
A
Step-by-step explanation:
The domain of a function is the span of x-values covered by the graph.
From the graph, we can see that it stretches from x=-7 to x=2.
However, note that at x=-7, the dot is closed (shaded in). In other words, x=-7 <em>is</em> in our domain.
On the other hand, at x=2, the dot is not shaded. So, x=2 is <em>not</em> included in our domain.
Therefore, our domain all are numbers between -7 and 2 including -7 (and not including 2).
As a compound inequality, this is:

So, our answer is A.
Also note that we use x instead of p(x) because the domain relates to the x-variable. If we were to instead find the range, then we would use p(x).