All categories

3 years ago

If F(x) = 2x^ln(x), then F'(2) =

Mathematics

2 answers:

joja [24]3 years ago

8 0

2=3x4m3Aojsksh=20jsjsjsjshxoxdd

pantera1 [17]3 years ago

7 0

Answer:

eln2(x)ln(x4)/x

I HOPE THIS HELPED!

Step-by-step explanation:

You might be interested in

the cost of parking of an hourly lot can be represented by the following equation y=3x+2. what does the 3 tell you about the cos

vitfil [10]

3 is How many hours they spent in the parking lot.

5 0

3 years ago

Read 2 more answers

Insert <, >, or = in the appropriate space to make a true statement.

Harman [31]

Answer:

Step-by-step explanation:

1 - 3 ?? -4

-2 ?? -4

The appropriate symbol for this ?? relation is >.

1 -3 > -4

6 0

3 years ago

Find the absolute maximum and absolute minimum values, if any, of the function. (If an answer does not exist, enter DNE.)f(x) =

lyudmila [28]

Answer:

The absolute minimum value is " $-\frac{21}{4}$ " and the absolute maximum value is " $15$ ".

Step-by-step explanation:

Given:

$f(x)=x^2-x-5$

on,

$[0,5]$

By differentiating it, we get

⇒ $f'(x)=2x-1$

Set $f'(x)=0$

then,

⇒ $2x-1=0$

$2x=1$

$x=\frac{1}{2}$ (Critical point)

When x=0,

⇒ $f(x)=-5$

When $x=\frac{1}{2}$ ,

⇒ $f(x)=-\frac{21}{4}$ (Absolute minimum)

When $x=5$

⇒ $f(x)=15$ (Absolute maximum)

7 0

2 years ago

kicyunya [14]

Answer:

8.69% probability that at least 285 rooms will be occupied.

Step-by-step explanation:

For each booked hotel room, there are only two possible outcomes. Either there is a cancelation, or there is not. So we use concepts of the binomial probability distribution to solve this question.

However, we are working with a big sample. So i am going to aproximate this binomial distribution to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

In this problem, we have that:

A popular resort hotel has 300 rooms and is usually fully booked. This means that $n = 300$

About 7% of the time a reservation is canceled before the 6:00 p.m. deadline with no pen-alty. What is the probability that at least 285 rooms will be occupied?

Here a success is a reservation not being canceled. There is a 7% probability that a reservation is canceled, and a 100 - 7 = 93% probability that a reservation is not canceled, that is, a room is occupied. So we use $p = 0.93$