Well a clock has twelve hours that make up a full circle, or 360 degrees, so you divide 12 by 360 then multiply by the degree, which in this case is 81.81 and that's the number of hours. (You figure out the minutes by looking at the decimal)
Answer:
#5
Area = Area of bigger triangle - Area of small triangle

#8
Area = area of square + area of two right angled triangles

Answer:
bool b = isupper(x);
Step-by-step explanation:
I have written the expression for a char variable x.The isupper(x) will return true if the character x is upper case and false if the character x is lower case.
I have stored the returned value to a bool variable b .So the value of variable b will be true only when the x is in uppercase and false when b is lower case.
1.) v=(l)(w)(h)
V=(9)(9)(9)
V=(81)(9)
V=729in^3
2.) (I forget if this is the real equation to this but this would give you the same answer)
V=(l)(w)(h)
————
2
V=(8)(6)(12)
————-
2
V=576/2
V=288cm^3
Answer:

Step-by-step explanation:
hope this helps!