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mojhsa [17]
3 years ago
7

Please help me with this statistical question if you can, it would mean alot im really struggling right now

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
3 0

Answer:

vcc bc cvfdf

Step-by-step explanation:

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Problem 1: Given the following probabilities P(Ac) = 0.45, P(B) = 0.34, and P(B|A) = 0.23. Find the following probabilities:
-BARSIC- [3]

Answer:

P(A)=0.55

P(A and B)=P(A∩B)=0.1265

P(A or B)=P(A∪B)=0.7635

P(A|B)=0.3721

Step-by-step explanation:

P(A')=0.45

P(A)=1-0.45=0.55

P(B∩A)=?

P(B|A)=0.23

P(B|A)=(P(A∩B))/P(A)

0.23=(P(A∩B))/0.55

P(A∩B)=0.23×0.55=0.1265

P(A∪B)=P(A)+P(B)-P(A∩B)

=0.55+0.34-0.1265

=0.7635

P(A|B)=[P(A∩B)]/P(B)=0.1265/0.34 ≈0.3721

8 0
3 years ago
What is the formula for the circumference of a circle?
Juli2301 [7.4K]

Answer:

C = pi * d = 2 * pi *r

Step-by-step explanation:

The circumference of a circle is the distance around the circle.  It can be found by multiplying the diameter times pi.

C = pi * d

We can replace the diameter with twice the radius

C = pi * 2 * r = 2 * pi *r

5 0
3 years ago
Name the intersection of AB and CD
Vlad1618 [11]

Answer:

two lines, AB and CD, intersect at point E. find the values of x and y given that: the measure of angle AED equals (10x+9y), the measure of angle AEC equals (xy), and the measure Algebra -> Angles -> SOLUTION: two lines, AB and CD, intersect at point E. find the values of x and y given that: the measure of angle AED equals (10x+9y), the measure of angle AEC equals (xy), and the measure Log On

Step-by-step explanation:

7 0
3 years ago
How to find the median of <br><br> E)6,10,12,5,7,12,9
emmasim [6.3K]
First you order them from least to greatest.

5, 6, 7, 9, 10, 12, 12

Then you cross off one number from each side until you get to the middle

Medial = 9
6 0
3 years ago
Read 2 more answers
The product of two consecutive numbers exceeds the square
Lyrx [107]

Answer:

20,21

Step-by-step explanation:

Let x be the first number.

Let y be the 2nd number.

Given y - x = 1 (since they are consecutive)

Rearrange it: y = x+1 (equation 1)

Also given:

xy-20=x^{2} (equation 2)

Now we can substitute y = x + 1 into equation 2.

x(x+1)-20 = x^{2} \\x^{2} +x-20 = x^{2} \\x-20=x^{2} -x^{2} \\x-20=0\\x=20

Since we know x, the smaller number is 20, we can substitute to equation 1 to find y, the larger number.

y = 20+1

= 21.

Therefore the 2 numbers are 20 and 21.

8 0
1 year ago
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