The denominator of the raised fraction is what goes on the outside of the square root. So if you had 2 raised to 1/3, you'd put the 3 raised outside to the left of the radical and the 2 inside. They give the same answer, so if you know one, you can always play with the other until you get the same answer. My teacher told us in Calculus a funny/weird way to remember it is the "bottom (of the raised fraction) goes in the crack (of the radical)." Does this help??
A. 2x+y=25; x+y=20
x represents cheese wafers and y represents chocolate wafers.
B. I will choose elimination since there is y and y. I can multiply one equation by -1 to get y and -y, which cancels out.
2x+y=25
-x-y=-20
Add equations
x=5
Plug x in
5+y=20
y=15
Final answer: 5 cheese wafers, 15 chocolate wafers
Answer:
the sum of two irrational numbers
Step-by-step explanation:
nada más estoy respondiendo para poder passar jmuna cosa aqui
Step-by-step explanation:
haha
Notice that 6 is a factor of all three coefficients and thus can be factored out:
6x^2 -42x-54 => 6(x^2 - 7x - 9). x^2 - 7x - 9 does not factor so easily. Remembering that obtaining roots of a quadratic makes it easy to write out the corresponding factors, let's apply the quadratic formula to x^2 - 7x - 9:
a=1, b = -7, c = -9. Then the discriminant is b^2 - 4ac, or (-7)^2 - 4(1)(-9), or 85.
Thus, the roots are:
7 plus or minus √85 7 plus or minus 9.220
x = -------------------------------- = ------------------------------------
2 2
Let's call these roots "a" and "b." Then the factors of the quadratic x^2 - 7x - 9 are (x-a) and (x-b), or, in this case, (x-8.11) and (x+1.11).
The original quadratic has three factors: 6, (x-8.11) and (x+1.11).
