N+(n+1)+(n+2)+(n+3)+(n+4)+(n+5)=270
We use these terms to represent the first six consecutive integers in the sequence
Now we group like terms:
6n+15=270
Minus 15 from both sides of the equation
6n=255
n=42.5 which is not an integer
Is this a joke question?
Besides that, the 2nd number will be 43.5
Answer:
c
Step-by-step explanation:
Answer:
Midpoint of AB = (0 + 2a / 2 , 0 + 0 / 2) = (2a / 2 , 0 / 2) = (a,0)
x coordinate of point c = a
N = (0 + a / 2 , 0 + b / 2) = (a / 2 , b / 2)
M = ( 2a + a / 2 , 0 + b / 2) = (3a / 2 , b / 2)
MA = √(3a / 2 - 0)² + b / 2 - 0)²
= √(3a / 2 )² + (b / 2) = 9a² / 4 + b² / 4
NB = √(a / 2 - 2a)² + (b / 2 - 0 )²
= √( a / 2 - 4a / 2)² + (b / 2 - 0)²
= √(-3a / 2)² + (b / 2)² = √9a² / 4 + b² / 4
Step-by-step explanation:
I tried my best hope its correct :0
Answer:
(+)6
Step-by-step explanation:
Grow means it will be positive and 6 means it will be, well, 6
