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Papessa [141]
3 years ago
14

Is this a polynomial, if so whats the degree

Mathematics
1 answer:
IRINA_888 [86]3 years ago
5 0

Answer:

where is the polynomial (?)

Step-by-step explanation:

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PLEASE HELP ASAP, I NEED A PERFECT SCORE. I'M IN A STRESS AND PANIC MODE BECAUSE I MAY NOT FINISH 9TH GRADE, PLZ HELP ME ANSWER
grandymaker [24]
M(x) = 5x + 4     n(x) = 6x - 9

Part 1 (m + n)(x) = 5x + 4 + 6x - 9
                           = 11x - 5

Part 2 (m * n)(x) = (5x + 4)(6x - 9) = 30x^2 - 21x - 36

Part 3 m[n(x)] = 5(6x - 9) + 4
                       = 30x - 45 + 4
            = 30x - 41
5 0
3 years ago
Gavin deposited $516 into a special savings account that earns 6.25% interest after 1 year. If Gavin doesn’t deposit any money i
tiny-mole [99]

Answer:

The amount of interest earned after a year is $32.25

Step-by-step explanation:

In this question, we are asked to calculate the amount of interest generated by depositing a sum into an account.

To calculate the interest earned, we use the simple interest formula.

Mathematically;

I = PRT/100

where I is the interest earned

R is the rate which is 6.25% according to the question

T is the time taken which is 1 year

P is the amount of money deposited also know. as the principal which is $516

Plugging these values we have

I = (516 * 6.25 * 1)/100 = $32.25

6 0
2 years ago
Identify the segment bisector of QR. Then find QR. *
Fittoniya [83]

Answer:

Ok so QR=10 because x=5 and the bisector I believe is LM :)

Step-by-step explanation:

5 0
2 years ago
Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. n = 195,
Semenov [28]
Given:
n = 195, sample size.
x = 162, successes in the sample

The proportion is
p = x/n = 162/195 = 0.8308

n* p = 195*0.8308 = 162
n*(1-p) = 195*(1 - 0.8308) = 33
If n*p >= 10, and n*(1-p) >= 10, then the sample proportions will have a normal distribution. This condition is satisfied.

The proportion mean is
μ = 0.8308
The proportion standard deviation is
\sigma =  \sqrt{ \frac{p(1-p)}{n} }  = \sqrt{ \frac{0.8308(1-0.8308)}{195} } =0.0269

σ/√n = 0.0269/√195 = 0.00192

At the 95% confidence level, the interval for the population proportion is
(μ - 1.96(σ/√n), μ + 1.96(σ/√n))
= (0.8308 - 1.96*0.00192, 0.8308 + 1.96*0.00192)
= (0.827, 0.8345)

Answer: The 95% confidence interval is (0.827, 0.835)








5 0
3 years ago
We need standard units to measure the physical quantity <br>​
Gekata [30.6K]

Answer:

true

Step-by-step explanation:

7 0
3 years ago
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