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NNADVOKAT [17]
3 years ago
11

Whats yall favv scary movie

Computers and Technology
1 answer:
GrogVix [38]3 years ago
6 0

Answer:

the omen lol

Explanation:

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Analyze the following code:
olganol [36]

Answer:

The program displays 5 4 3 2 1 and then raises an Array Index Out Of Bounds Exception.

Explanation:

A sample of code output is attached.

The code snippet contain xMethod that takes an array and array length as argument.

In the given snippet, the array {1, 2, 3, 4, 5} and length (5) is passed as argument to the method.

First the method display the element of the array in reverse order

System.out.print(" " + x[length - 1]);

and then the method call itself again. This displays

5 from x[4]

4 from x[3]

3 from x[2]

2 from x[1]

1 from x[0]

but after displaying 1, when it tries to call the method again, an array index out of bound exception is thrown because it will try accessing an element from the array when it is already exhausted.

5 0
3 years ago
Write a program for Horizon Phones, a provider of cellular phone service. Prompt a user for maximum monthly values for talk minu
Anarel [89]

Answer:

mport java.util.Scanner;

public class CellPhoneService

{

    public static void main (String args[])

    {

         Scanner sc=new Scanner(System.in);

         System.out.println("Enter the Talk minutes");

         int talkmin=sc.nextInt();

         System.out.println("Enter the text message");

         int textmsg=sc.nextInt();

         System.out.println("Enter the Gigabyte Data");

         int gbdata=sc.nextInt();

         if(talkmin<500 && textmsg==0 && gbdata==0)

         System.out.println("PLAN A IS RECOMMENDED FOR THIS USER at 49$ per month");

         else if(talkmin<500 && textmsg>0 && gbdata==0)

         {

              System.out.println("PLAN B IS RECOMMENDED FOR THIS USER at 55$ permonth");

         }

         else if(talkmin>=500 && textmsg<100 && gbdata==0)

         {

              System.out.println("PLAN C IS RECOMMENDED FOR THIS USER at 61$ permonth");

         }

         else if(talkmin>=500 && textmsg>=100 && gbdata==0)

         {

              System.out.println("PLAN D IS RECOMMENDED FOR THIS USER at 70$ permonth");

         }

         else if(gbdata>0 && gbdata<2)

         {

              System.out.println("PLAN E IS RECOMMENDED FOR THIS USER at 79$ permonth");

         }

         else if(gbdata>=2)

         {

              System.out.println("PLAN F IS RECOMMENDED FOR THIS USER at 87$ permonth");

         }

    }

}

Explanation:

  • Take the talk minute and text message as input from user.  
  • Apply the conditional statement to check if talk minute is less than 500 along with text message and GB data having a value 0.
  • At last check if GB data is greater than or equal to 2, then print the relevant response.
3 0
4 years ago
You designed a program to create a username using the first three letters from the first name and the first four letters of the
Pavel [41]

Answer:

See Explanation

Explanation:

The question would be best answered if there are options to select from; since none is provided, I will provide a general explanation.

From the question, we understand that, you are to test for Jo Wen.

Testing your program with this name will crash the program, because Jo has 2 letters (3 letters are required), and Wen has 3 letters (4 letters are required)

So, the step that needs to be revisited is when the username is generated.

Since the person's name cannot be changed and such person will not be prevented from registering on the platform, you need to create a dynamic process that handles names whose lengths are not up to the required length.

7 0
3 years ago
If you're driving a car and know there's a motorcyclist around you, you should______. A. Not change your driving B. Check your b
Sedaia [141]

b check your blind spots frequently i guess not sure

5 0
3 years ago
In Python please.
SOVA2 [1]

Answer:

negatives = []

zeros = []

positives = []

while True:

   number = input("Enter a number: ")

   if number == "":

       break

   else:

       number = int(number)

       if number < 0:

           negatives.append(number)

       elif number == 0:

           zeros.append(number)

       else:

           positives.append(number)

for n in negatives:

   print(n)

for z in zeros:

   print(z)

for p in positives:

   print(p)

Explanation:

Initialize three lists to hold the numbers

Create a while loop that iterates until the user enters a blank line

Inside the loop:

If the number is smaller than 0, put it in the negatives list

If the number is 0, put it in the zeros list

Otherwise, put the number in the negatives list

When the while loop is done, create three for loops to print the numbers inside the lists

5 0
3 years ago
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