from what I know
A=4
B=3
C=2
and a plus adds 0.33 and a minus minuses 0.33
question wants us to find yearly average or average per 1 year
since these grades span over 2 years, we must divide the total average by 2
averagefresh=sum of fresh grades/4 grades per year
averagesoph=sum of soph grades/4 grades per year
yearlyaverage=(averagefresh+averagesoph)/2
freshman:
(C)+(B)+(A)+(C-)=2+3+4+(2-0.33)=10.67
sophomore:
(B+)+(A-)+(C+)+(B-)=(3+0.33)+(4-0.33)+(2+0.33)+(3-0.33)=12
averagefresh=10.67/4=2.6675
averagesoph=12/4=3
yearlyaverage=(2.6675+3)/2=2.83375
so it's about a average
Answer:
4 cm 2
Step-by-step explanation:
You can solve for A:
A= 1/6 p^2 =1/16 times 8^2 =4cm^2
(^ means exponet)
A, D, E and F are all true statements.
When looking for congruence in these type of problems, you have to look for the order of the letters in the original listing. Since they are listed LMN and PQR, this means we have to focus on the placement of those letters. Since L is the first listed in the sequence, it is congruent with P, which is also listed first. M is congruent with Q since they are both in the middle, and N and R are congruent since they are both at the end.
Now to find true statements, you need to make sure everything matches up in the statement.
Let's take A for instance. It states that MN = QR. Now we know M is in the middle and N is at the end. Since Q is in the middle and R is at the end, they match and are therefore true.
Answer:
-1.7x -3
Step-by-step explanation:
−4.2x+3 +2.5x−6
I like to line them vertically
−4.2x+3
2.5x−6
------------------
-1.7x -3