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3 years ago

Match each statement with the property it illustrates.

1 answer:

8 0

1- Associative property of addition: E
-1+(4+9)=(-1+4)+9

2- Commutative property of multiplication: A
(-9)(0)=(0)(-9)

3- Commutative property of addition: D
-9+1=1+(-9)

4- Identity property of addition: B
-9+0=-9

5- Identity property of multiplication: F
(-9)(1)=-9

6- Associative property of multiplication: C
-1(4•9)=(-1•4)9

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4. If your company purchases an annuity that will pay $50,000/year for 10 years at a 11% discount rate, what is the value of the

julsineya [31]

Answer:

The value of the annuity is $326,852.3766.

Step-by-step explanation:

Here is the required formula to find the present value of annuity:

We can find the present value of annuity:

$PV = P + P (\frac{1-(1+r)^{-(n-1)} }{r})$

Here:

P = $50,000

n = represents the number of number of periods

r = 0.11

$PV = 50,000 + 50,5000 (\frac{1-(1+0.11)^{-(10-1)} }{0.11})$

PV = $326,852.3766

The value of the annuity is $326,852.3766 i.e. PV = $326,852.3766.

Keywords: discount rate, present value of annuity

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3 years ago

The area of the shaded segment is 100cm^2. Calculate the value of r.

Reil [10]

Hello,

The formula for finding the area of a circular region is: $A= \frac{ \alpha *r^{2} }{2}$

then:
$A_{1} = \frac{80*r^{2} }{2}$

With the two radius it is formed an isosceles triangle, so, we must obtain its area, but first we obtain the height and the base.

$cos(40)= \frac{h}{r} \\ \\ h= r*cos(40)\\ \\ \\ sen(40)= \frac{b}{r} \\ \\ b=r*sen(40)$

Now we can find its area:
$A_{2}=2* \frac{b*h}{2} \\ \\ A_{2}= [r*sen(40)][r*cos(40)]\\ \\A_{2}= r^{2}*sen(40)*cos(40)$

The subtraction of the two areas is 100cm^2, then:

$A_{1}-A_{2}=100cm^{2} \\ (40*r^{2})-(r^{2}*sen(40)*cos(40) )=100cm^{2} \\ 39.51r^{2}=100cm^{2} \\ r^{2}=2.53cm^{2} \\ r=1.59cm$

Answer: r= 1.59cm

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3 years ago

Read 2 more answers

Given: f(x) = 2x + 5 and g(x) = x2 and h(x) = -2x<br><br> h(g(f(x)))

alexgriva [62]

Hello here is a solution :
<span>h(g(f(x))) ?

</span>g(f(x))= g(2x+5)=(2x+5)²=(2x)²+2(2x)(5)+5² = 4x²+20x+25
h(g(f(x)))(x) = h(4x²+20x+25) = -2(4x²+20x+25)
h(g(f(x)))(x) = -8x²-40x-50

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3 years ago

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Which decimals are less than 2.312 select all that apply A. 2.311. B.2.4 C.2.32 D.2.3 E.2.31 F.2.313

fgiga [73]

Answer:

A, D, E

Step-by-step explanation:

I hope this is correct

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3 years ago

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For the piecewise function, find the values h( - 6), h(0), h(5), and h(9).- 5x – 13, for x < -3h(x) = { 5, for - 35x<5for

sleet_krkn [62]

Given the piecewise function h(x):

$h(x)=\begin{cases}-5x-13,x$

-When x is less than "-3", h(x)=-5x-13

-When x is between -3 and 5, h(x)=5

-When x is greater than or equal to 5, h(x)=x+1

1) For h(-6), this notation indicates that you have to determine the value of h(x) when x=-6

-6 is less than -3, which means that for this value of x, the function has the following shape

$h(x)=-5x-13$

Replace the expression with x=-6 and calculate the corresponding value of x:

$\begin{gathered} h(-6)=-5(-6)-13 \\ h(-6)=30-13 \\ h(-6)=17 \end{gathered}$

2) For h(0), you have to determine the value of h(x) when x=0. Zero is between -3 and 5, for this value of x, the function h(x) has the following shape:

$h(x)=5$

This equation represents a horizontal line, which means that for every value within the interval of definition -3≤x<5, the function always has the same value h(x)=5

We can conclude that: