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3 years ago

Select all the relations that represent a function.

Mathematics

2 answers:

frosja888 [35]3 years ago

4 0

Skdiogoffofiidjfjfdhdhxididi

Delvig [45]3 years ago

3 0

Answer:

1. (1, 3), (2, 5), (2, 7) (4,9) No

2. (1, 3), (2, 5), (3, 7) (4,9) Function

3. (1, 3), (1,5), (1, 7) (4, 9) No

4. (1,3), (2, 3), (3, 3) (4, 3) Function

5. (1, 2), (2, 5), (2, 1) (4, 5) No

Step-by-step explanation:

If you see the same x-coordinate more than once in a relation, then that relation is not a function.

1. (1, 3), (2, 5), (2, 7) (4,9) The 2 is used more than once as a x-coordinate. Not a function.

2. (1, 3), (2, 5), (3, 7) (4,9) All x-coordinates are different. Function.

3. (1, 3), (1,5), (1, 7) (4, 9) The 1 is used more than once as an x-coordinate. Not a function.

4. (1,3), (2, 3), (3, 3) (4, 3) All x-coordinates are different. Function.

5. (1, 2), (2, 5), (2, 1) (4, 5) The 2 is used more than once as a x-coordinate. Not a function.

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Answer:

$22,200

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Step-by-step explanation:

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If there are 12 boys and 60 girls in a room, fill out all of the possible ratios of boys to girls that could be made.

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Answer:

6:30

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Step-by-step explanation:

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3 years ago

To go to school each day, Myra walks 20 yards due south to the bank then 48 yards east. Which measurement is closest to the shor

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3 years ago

Read 2 more answers

What is the value of X?

algol [13]

Answer:

x = 3

Step-by-step explanation:

ΔABC is 45 45 90 right triangle

The ratio of leg: hypo = a : a√2

Given: hypo AC = 6√2; so AB = BC = 6

ΔBCD is 30 60 90 right triangle

The ratio of short leg : long leg : hypo = x : x√3 : 2x

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3 years ago

Solving Rational Inequalities and use sign diagram to sketch the graph. Image attached for better understanding.

Digiron [165]

Answer:

x ∈ (-∞, -1) ∪ (1, ∞)

Step-by-step explanation:

To solve this problem we must factor the expression that is shown in the denominator of the inequality.

So, we have:

$x ^ 2-1 = 0\\x ^ 2 = 1$

So the roots are:

$x = 1\\x = -1$

Therefore we can write the expression in the following way:

$x ^ 2-1 = (x-1)(x + 1)$

Now the expression is as follows:

$\frac{(x-2) ^ 2}{(x-1) (x + 1)}\geq0$

Now we use the study of signs to solve this inequality.

We have 3 roots for the polynomials that make up the expression:

$x = 1\\x = -1\\x = 2$

We know that the first two are not allowed because they make the denominator zero.

Observe the attached image.

Note that:

$(x-1)\geq0$ when $x\geq-1$

$(x + 1)\geq0$ when $x\geq1$

and

$(x-2) ^ 2$ is always $\geq0$

Finally after the study of signs we can reach the conclusion that:

x ∈ (-∞, -1) ∪ (1, 2] ∪ [2, ∞)

This is the same as

x ∈ (-∞, -1) ∪ (1, ∞)

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3 years ago