Find length CD first, which is the hypotenuse of the triangle.
PD = opposite
Opposite & hypotenuse = SOH or sin
Sin(27) = 15/H
x h, then ÷ sin(27)
H = 15/sin(27)
H = 33.04....
Move to triangle CDR:
15 is length opposite the angle we're after.
So far, we've got the hypotenuse (which we just found to be 33.04....) & the opposite of our triangle
Hypotenuse & opposite = SOH
Sin(x) = 15/33.04... but, to find the angle we do inverse of sin
sin-1(15/33.04...) = x
x = 27
(33.04... means I used the full numbers displayed on my calculator)
Thus, RCD is 27 degrees
Hope this helps!
Answer:
its b
Step-by-step explanation:
Answer:
-10
Step-by-step explanation:
5 is lower than 15 so the answer must be negative
if 15 minus 5 is 10
then 5 minus 15 has to be 10
Answer:
(a) 680 km
(b) 680000 m
Step-by-step explanation:
(a) Distance run by hunter every day = 6.8 km
Total number of days under consideration = 100
So the total distance covered by the hunter = ![\[6.8 * 100\] ](https://tex.z-dn.net/?f=%5C%5B6.8%20%2A%20100%5C%5D%0A)
= 680 km
The hunter ran 680 km in the last 100 days.
(b) Converting this value to meters:
1 km = 1000 m
=> 680 km = 680 * 1000 m
= 680000 m
The equivalent distance run by the hunter when converted to meters is 680000 meters.
Rate of change = slope
slope = )y2 - y1) / (x2 - x1)
(0,-4)....x1 = 0 and y1 = -4 (pay attention to the negative sign when subbing)
(3,2)....x2 = 3 and y2 = 2
now we sub
slope(rate of change) = (2 - (-4) / (3 - 0) = (2 + 4) / 3 = 6/3 = 2 <==