Answer:
20 years
Step-by-step explanation:
Using the formula; A = P(1 + r)^t
We can plug in the known to find t
400 = 220(1.03)^t
then solve for t;
1.818 = 1.03^t
Introducing In
In 1.818 = t × In (1.03)
t = 20.225
t = 20 years to the nearest year
Answer:
-3/2
Step-by-step explanation:
Here we have an ambiguous notation. Hence, I assume you mean (-12/((3 x (-8+ (-4)^2 -6) +2), which is the one that makes more sense.
First, we work the arithmetic on the denominator (D).
D= 3 x (-8 + (-4)^2 - 6) + 2
D=3 x (-8 + (-4) x (-4) -6) + 2
D= 3x (-8 +16 -6) + 2
D= 3 x (2) + 2=6 + 2=8
Now, we just have to divide -12 by D to obtain the answer.
-12/D = -12/8 =(-2 x 2 x 3)/(2 x 2 x 2) = -3/2
Answer:
<h3>B. It has infinite solutions</h3>
Step-by-step explanation:
Given the system of equations:
2t + w = 10 ..... 1
4t = 20 − 2w ... 2
From 1:
w = 10-2t ...3
Substitute 3 into 2 to have;
4t = 20 - 2(10-2t)
4t = 20-20+4t
4t = 4t
Let t = k
Substitute t = k into 1 and get w;
From 1: 2t + w = 10
2k + w =10
w = 10 - 2k
<em>k can take any integers. This shows that the solution to the equation is infinite</em>
<em></em>
Functions cannot have the same X value (the first number), but they can have the same Y value (the second number).
<span>A. {(1,2),(2,3),(3,4),(2,1),(1,0)}
B. {(2,−8),(6,4),(−3,9),(2,0),(−5,3)}
C. {(1,−3),(1,−1),(1,1),(1,3),(1,5)}
D. {(−2,5),(7,5),(−4,0),(3,1),(0,−6)}
Choice A. has two repeating X values [(1,2) and (1,0), (2,3) and (2,1)]
Choice B. has one repeating X value [(2, -8) and (2,0)]
Choice C. all has a repeating X value (1)
Choice D doesn't have any repeating X values.
In short, your answer would be choice D [</span><span>{(−2,5),(7,5),(−4,0),(3,1),(0,−6)}] because it does not have any repeating X values.</span>
