The equation in slope intercept form for the line with slope 3 and Y intercept -1 is y = 3x -1 .
Y=11x/20 +.25
<span>Solve for </span><span>y</span><span> by </span>simplifying<span> both sides of the </span>equation<span>, then isolating the </span>variable<span>.</span>
Answer:
First, find tan A and tan B.
cosA=35 --> sin2A=1−925=1625 --> cosA=±45
cosA=45 because A is in Quadrant I
tanA=sinAcosA=(45)(53)=43.
sinB=513 --> cos2B=1−25169=144169 --> sinB=±1213.
sinB=1213 because B is in Quadrant I
tanB=sinBcosB=(513)(1312)=512
Apply the trig identity:
tan(A−B)=tanA−tanB1−tanA.tanB
tanA−tanB=43−512=1112
(1−tanA.tanB)=1−2036=1636=49
tan(A−B)=(1112)(94)=3316
kamina op bolte
✌ ✌ ✌ ✌
Answer:
C. It cannot be factored into a perfect square.
Step-by-step explanation:
Take the square roots of all the numbers present (64, 49, 8) and you will find that 8, the constant, is not a perfect square.
