The number of passwords that would be allowed if users were allowed to reuse the letters and numbers is 30891577600
<h3>How to determine the number of passwords</h3>
The given parameters are:
Password length = 8
Letters = 6
Numbers = 2
There are 26 letters and 10 digits.
Since the letters and the numbers can be repeated, then the number of passwords is:
Count = 26^6 * 10^2
Evaluate
Count = 30891577600
Hence, the number of passwords that would be allowed if users were allowed to reuse the letters and numbers is 30891577600
Read more about combination at:
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Move the decimal five places until it is after one number, and because the number got bigger, your exponent is a negative.
Answer:
Part A: Triangles GCB and PBE
Part B: They're similar because they have the same internal angles.
Part C:
250/400 = BE/450
112500/400 = BE
BE = 281.25 ft
250/400 = PE/350
87500/400 = PE
PE = 218.75 ft
ANSWER
M=(−3,72)
Find A midpoint calculator on the internet
8) A. x + 2,
2) B. f(x) = (x -3) (x +9).
Step-by-step explanation:
Step 1; If the function equals 0, we substitute all the separate factors to 0. We keep the variable on the left side while all the other values go to the right side.
If f(x) = (x +3) (x -9) = 0, then x +3 = 0, x -9 = 0. So x = -3 and x = 9.
If f(x) = (x -3) (x +9) = 0, then x -3 = 0, x +9 = 0. So x = 3 and x = -9.
If f(x) = (x -3) (x -9) = 0, then x -3 = 0, x -9 = 0. So x = 3 and x = 9.
If f(x) = (x +3) (x +9) = 0, then x +3 = 0, x +9 = 0. So x = -3 and x = -9.
So if the factors are 3 and -9, option B is an answer.
Step 2; For the given graph, the same applies. The graph passes through the points of (-2, 0) and (4, 0) on the x-axis.
So if x = -2, then x +2 = 0 and if x = 4, x -4 = 0. The first equation is option A while the second equation is not given.
