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Slav-nsk [51]
3 years ago
7

An apartment complex offers 15 apartments with a view of the river, 8 with two bedrooms, and 6 that have both selections. How ma

ny only have a view of the river?
Mathematics
1 answer:
djyliett [7]3 years ago
3 0

Answer:

9

Step-by-step explanation:

Otf the 15 that have a view of the river, 6 have both selections.

The remaining 9 only have a view of the river.

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Find angle A using sin-1
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Answer:

75°

Step-by-step explanation:

firstly, use the pythagoras theorem

Square root(8²-2²) = 7.75

Then, use sine

sine A= 7.75/8

Sine A=0.9688

A= (sine power of -1) x (0.9688)

A=75.63

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Classify the four angles of the quadrilateral.
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Answer:

<A= right

<B= acute

<C= obtuse

<D= acute

Step-by-step explanation:

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What is true about any point on a coordinate plane with a negative x-coordinate and a y-coordinate that is not zero?
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999,765 rounded to the nearest hundred thousand
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Read 2 more answers
A source of laser light sends rays AB and AC toward two opposite walls of a hall. The light rays strike the walls at points B an
Nataly [62]

Answer:

The distance between the walls is 70 m.

Step-by-step explanation:

Given: A source of laser light is at point A on the ground between two parallel walls BE and CD . The walls are perpendicular to the ground that is

BE ⊥ ED and CD ⊥ ED

AB is a ray of light which strikes the wall on the left at point B which is 30 meters above the ground. that is BE = 30 m

AC is a ray of light which strikes the wall on the right at point C. The length of AC = 80 meters.

The ray AB makes an angle of 45 degrees with the ground that is m∠BAE = 45°

The ray AC makes an angle of 60 degrees with the ground that is m∠CAD = 60°

As shown is figure attached below.

WE have to find the distance between the walls that is Length of ED

Length of ED = EA + AD

Consider the Δ AEB,

Using trigonometric ratio,

\tan\theta=\frac{perpendicular}{base}

Here \theta=45^{\circ} , perpendicular = 30 m  and base we can find.

thus,

\tan 45^{\circ}=\frac{30}{EA}

We know \tan 45^{\circ}=1

thus, EA =  30 m

Consider the Δ AEB,

Using trigonometric ratio,

\cos\theta=\frac{base}{hypotenuse}

Here \theta=60^{\circ} , hypotenuse = 80 m  and base we can find.

thus, \cos 60^{\circ}=\frac{base}{80}

We know, \cos 60^{\circ}=\frac{1}{2}

thus, Base = 40 m

AD = 40 m

Thus, the distance between the walls that is the length of ED = 30 + 40 = 70 m

4 0
3 years ago
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