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3 years ago

There are some oranges in a box. The total weight of these oranges is 4.29 kg. The

Mathematics

1 answer:

-BARSIC- [3]3 years ago

3 0

Answer:

There are 44 oranges in the box

Step-by-step explanation:

4.29 kg = 4290 g

4290g / 97.5 g = 44

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Solve 7x+6<3(x - 2).

lawyer [7]

Answer:

x<−3

Step-by-step explanation:

hope this works

4 0

3 years ago

You need to solve for X

zhenek [66]

Look at the picture.

We have the proportion:

$\dfrac{x}{2}=\dfrac{305}{122}\ \ \ \ |\cdot2\\\\x=\dfrac{305}{61}\\\\x=5\ ft$

Answer: Rayan is 5 ft tall.

5 0

4 years ago

Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviat

drek231 [11]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

Step-by-step explanation:

For this case we have the following probability distribution given:

X 0 1 2 3 4 5

P(X) 0.031 0.156 0.313 0.313 0.156 0.031

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

We can verify that:

$\sum_{i=1}^n P(X_i) = 1$

And $P(X_i) \geq 0, \forall x_i$

So then we have a probability distribution

We can calculate the expected value with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

6 0

3 years ago

Which equation does not represent the percentage of the votes?

Vladimir [108]

I would say 92 * x = 115

5 0

3 years ago

Divide by 2 digit divisors

ki77a [65]

837 divided by 36 equals 23.25

1650 divided by 55 equals 30

5634 divided by 18 equals 313

5226 divided by 52 equals 100.5

finally

5624 divided by 46 equals 122.2608695652174

7 0

4 years ago