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Ksivusya [100]
3 years ago
11

"tis greater than zero and less than or equal to 5" Complete the following steps to receive full credit for this question: . The

inequality translated in numerical form • The solution graphed on a number line • The solution in interval notation​
Mathematics
1 answer:
Shalnov [3]3 years ago
8 0

Answer:

A) 0 ≤ x ≥ 5

B) Number line is attached

C) Interval notation is; (0,5)

Step-by-step explanation:

We are told that the number is greater than zero and less than or equal to 5. If the number is x, then we can write the inequality as;

i) 0 ≤ x ≥ 5

ii) The solution graphed on a number line is attached.

iii) Since 0 ≤ x or x ≥ 5, then the interval notation is; (0,5)

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The Falcons had 3 fewer than twice as many Bears players. If the Falcons had 11 players, how many players were on the Bears?
Dmitry [639]
Subtraction, 11-3 is 8
Ps:trick question
3 0
2 years ago
Help ASAP<br>10 POINTS<br>find surface area and volume​
Arte-miy333 [17]
Cylinder (A):
-Surface area: adding all areas of all faces of the shape.

*10 x 6= 60m^3
*3.14 x 3^2 = 28.274 m^2. Then We times it by 2 since we have 2 circles. Which equals to 56.55m^2

Total surface area: 60 + 56.55 = 116.55m^2

-Volume: 3.14 x r^2 x h, then substitute.

*3.14 x 3^2 x 10 = 282.74m^3

(B):
-surface area:

*7 x 11= 77
*5 x 11 = 55
*11 x 11 = 121
*7 x 5 = 35/2 = 17.5 > then again we times it by 2 cuz we have 2 triangles. Which equals to 35.

Total surface area: 77 + 55 + 121 + 35 = 288 cm^2

-Volume:
*7 x 5 x 11 = 385 cm^3

Make sure to check the units!!!
Hope this helped :)
3 0
3 years ago
Evaluate BD for A = 5, B = -2, C = 4 and D = -6.
bezimeni [28]
B*D?
B=-2
D=-6
B*D=(-2)*(-6)=12
5 0
2 years ago
Read 2 more answers
Someone please help me
allsm [11]

Answer:

Solutions: x = \frac{-3}{ 4} + i \sqrt{39},  x = \frac{-3}{4} - i \sqrt{39}

Step-by-step explanation:

Given the quadratic equation, 2x² + 3x + 6 = 0, where a =2, b = 3, and c = 6:

Use the <u>quadratic equation</u> and substitute the values for a, b, and c to solve for the solutions:

x = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}

x = \frac{-3 +/- \sqrt{3^{2} - 4(2)(6)} }{2(2)}

x = \frac{-3 +/- \sqrt{9- 48} }{4}

x = \frac{-3 +/- \sqrt{-39} }{4}

x = \frac{-3 + i \sqrt{39} }{4}, x = \frac{-3 - i \sqrt{39} }{4}

Therefore, the solutions to the given quadratic equation are:

x = -\frac{3}{ 4} + i \sqrt{39} ,   x = -\frac{3}{4} - i \sqrt{39}

4 0
2 years ago
I neeeeeeeeeeeeeed help
masya89 [10]

9514 1404 393

Answer:

  14 +2i

Step-by-step explanation:

For this sort of problem, you can treat i as though it were a variable. Combine like terms.

  (8 -7i) +(6 +9i) = (8 +6) +(-7 +9)i

  = 14 +2i

7 0
3 years ago
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