4-3(x-y)=-8x+2
=4-3x-3y=-8x+2
=4-3x+8x-3y-2
=5x-3y+2
or
5x-3y=-2
so it will be C=5x+3y=-2
Answer:
Distance from the airport = 894.43 km
Step-by-step explanation:
Displacement and Velocity
The velocity of an object assumed as constant in time can be computed as
Where 
is the displacement. Both the velocity and displacement are vectors. The displacement can be computed from the above relation as
The plane goes at 400 Km/h on a course of 120° for 2 hours. We can compute the components of the velocity as
The displacement of the plane in 2 hours is
Now the plane keeps the same speed but now its course is 210° for 1 hour. The components of the velocity are
The displacement in 1 hour is
The total displacement is the vector sum of both
The distance from the airport is the module of the displacement:
Answer:
At a speed of 57 mph for 8 hr a driver will travel 456 mi
Step-by-step explanation:
Here we have a summary of the letters for each variable:
Speed ---> r (in units of mph)
Time ---> t (in units of hr)
Distance ---> d (in units of mi)
These three variables are related by the next formula:
d = rt
In the data they give to you: 57 mph and 8 hr, they are telling you the r and the t, respectively:
r = 57 mph
t = 8 hr
The only thing you have to do is replace the values:
d = rt ----> d = 57 mph x 8 hr
d = 456 mi
Square Root to the Nearest Tenth
A B
33 5.7
34 5.8
35 5.9
36 6
