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fredd [130]
3 years ago
11

‼️BRAINLIEST‼️ Samiha has a babysitting buisness that she earns $8 per hour she babysits. She already has $62. She wants to earn

enough money to buy a new phone for $350. Write an equation that represents how many hours she needs to babysit to earn the money to pay the phone?

Mathematics
2 answers:
alexgriva [62]3 years ago
8 0

Answer: 350-62= 288      288 divided by 8= 36

Step-by-step explanation:

polet [3.4K]3 years ago
5 0
The answer is 36 hope this helps a lot

mark me brainliest;))
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What is the 23rd term of the arithmetic sequence where a1 = 8 and a9 = 48?
joja [24]

Answer:

23rd term of the arithmetic sequence is 118.

Step-by-step explanation:

In this question we have been given first term a1 = 8 and 9th term a9 = 48

we have to find the 23rd term of this arithmetic sequence.

Since in an arithmetic sequence

T_{n}=a+(n-1)d

here a = first term

n = number of term

d = common difference

since 9th term a9 = 48

48 = 8 + (9-1)d

8d = 48 - 8 = 40

d = 40/8 = 5

Now T_{23}= a + (n-1)d

= 8 + (23 -1)5 = 8 + 22×5 = 8 + 110 = 118

Therefore 23rd term of the sequence is 118.

4 0
4 years ago
In circle V, angle WXZ measures 30°. Line segments WV,
PtichkaEL [24]

Answer:

120 On edge i got it right

Step-by-step explanation:

6 0
3 years ago
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A container holds 8 quarts of lemonade. How much is this in gallons?
Arturiano [62]

2 Gallons is 8 quarts.

8 0
4 years ago
Two cables support a 800​-lb ​weight, as shown. Find the tension in each cable.
jeka94

Answer:

  • 892 lb (right)
  • 653 lb (left)

Step-by-step explanation:

The weight is in equilibrium, so the net force on it is zero. If R and L represent the tensions in the Right and Left cables, respectively ...

  Rcos(45°) +Lcos(75°) = 800

  Rsin(45°) -Lsin(75°) = 0

Solving these equations by Cramer's Rule, we get ...

  R = 800sin(75°)/(cos(75°)sin(45°) +cos(45°)sin(75°))

     = 800sin(75°)/sin(120°) ≈ 892 . . . pounds

  L = 800sin(45°)/sin(120°) ≈ 653 . . . pounds

The tension in the right cable is about 892 pounds; about 653 pounds in the left cable.

_____

This suggests a really simple generic solution. For angle α on the right and β on the left and weight w, the tensions (right, left) are ...

  (right, left) = w/sin(α+β)×(sin(β), sin(α))

5 0
3 years ago
Please show step by step<br><br> a)6 ÷2(1+2)<br> b)48 ÷2(9+3)<br> c)9-3 ÷⅓ +1
UNO [17]

Answer:

1

Step-by-step explanation:

a)2 times 1 and then times 2 become (2+4) then 6 ÷ 6 (because 2 plus 4)

7 0
3 years ago
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