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Alexxandr [17]
2 years ago
12

For each statement below, determine whether the statement is a decision variable or not.

Mathematics
1 answer:
Zarrin [17]2 years ago
5 0

Answer and explanation:

Decision variables are variables that are independent(indeoendent variables) and can be controlled by the decision maker. Decision variables influence outcome or result of a solution, usually denoted x in linear programming.

Decision variables above include:

Number of Aqua-Spa Produced.

* Number of Hydro-Lux Produced.

* Number of Pumps Purchased.

* Amount of Available Labor Hours.

* Amount of Available Tubing Available

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An article describes a study in which a new type of ointment was applied to forearms of volunteers to study the rates of absorpt
Nuetrik [128]

Answer:

There were 70 choices for the four locations to apply the new ointment

Step-by-step explanation:

The order in which the locations are chosen is not important. So we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

How many different choices were there for the four locations to apply the new ointment

Four locations from a set of 8. So

C_{8,4} = \frac{8!}{4!(8-4)!} = 70

There were 70 choices for the four locations to apply the new ointment

3 0
3 years ago
Are the date still represented appropriately once you round the numbers?
nalin [4]
The correct answer is yes.
4 0
3 years ago
If a 90°degree angle is bisected, the two angles created by the bisector will equal?
katen-ka-za [31]

Answer:

45 degrees

Step-by-step explanation:

when an angle is bisected both angles formed are equal, so 90/2=45

5 0
3 years ago
Read 2 more answers
The diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 mi
Assoli18 [71]

Answer:

Probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.

Step-by-step explanation:

We are given that the diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 millimeters.

<em>Firstly, Let X = diameters of ball bearings</em>

The z score probability distribution for is given by;

          Z = \frac{ X - \mu}{\sigma} ~ N(0,1)

where, \mu = mean diameter = 106 millimeters

            \sigma = standard deviation = 4 millimeter

Probability that the diameter of a selected bearing is greater than 111 millimeters is given by = P(X > 111 millimeters)

    P(X > 111) = P( \frac{ X - \mu}{\sigma} > \frac{111-106}{4} ) = P(Z > 1.25) = 1 - P(Z \leq 1.25)

                                                  = 1 - 0.89435 = 0.1056

Therefore, probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.

4 0
2 years ago
Please help me with this!
mezya [45]

Answer:

y = \frac{6 - r}{r - m}

Please mark as brainliest

The picture is upside down

7 0
3 years ago
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