Answer: a - 4.512 hours
b - 1.94 hours
Step-by-step explanation:
Given,
a) A(t) = 10 (0.7)^t
To determine when 2mg is left in the body
We would have,
A(t) = 2, therefore
2 = 10(0.7)^t
0.7^t =2÷10
0.7^t = 0.2
Take the log of both sides,
Log (0.7)^t = log 0.2
t log 0.7 = log 0.2
t = log 0.2/ 0.7
t = 4.512 hours
Thus it will take 4.512 hours for 2mg to be left in the body.
b) Half life
Let A(t) = 1/2 A(0)
Thus,
1/2 A(0) = A(0)0.7^t
Divide both sides by A(0)
1/2 = 0.7^t
0.7^t = 0.5
Take log of both sides
Log 0.7^t = log 0.5
t log 0.7 = log 0.5
t = log 0.5/log 0.7
t = 1.94 hours
Therefore, the half life of the drug is 1.94 hours
Answer:
-1/10
Step-by-step explanation:
its down 1 and right 10 so you know the slope is -1/10
(can I get brainliest please)
On the unit cirlce, the cosine of an angle is negative whenever the angle falls in the interval
.
If you recall your special triangles, this cosine occurs for angles of
and
.
More generally, this occurs for
and
, where
is an integer.
Answer:
y = 2x - 9
Step-by-step explanation:
y2 - y1 / x2 - x1
9 - (-1) / 9 - 4
10 / 5
= 2
y = 2x + b
-1 = 2(4) + b
-1 = 8 + b
-9 = b
B. Do you see how there is a pi symbol next to 308, that means you don't have to multiply by pi so 967.61 but divided by
