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Fudgin [204]
3 years ago
12

A customer is late paying their renewal registration fee. The renewal registration fee is $142.16 and the late fee is 63% of the

renewal registration fee. In addition, the customer must also pay a $35.00 CHP late fee. What is the customer’s total balance due?
Mathematics
1 answer:
Andre45 [30]3 years ago
8 0
$124.56 because if you have 63% you change it to a decimal so it is not .63 and you multiply it by 146.16 and then add the 35 you get 124.56
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HELP!!!!!!!!!!!!!!!!!
jek_recluse [69]

Answer:

option A

Step-by-step explanation:

the statement tell us that she slides the triangle 2 units down, so the vertical axis is the one that we are going to modify

we have the points: (1,2), (3,3) and (4,1)

so to these points we subtract "2" to the variable Y

I mean:

(1,2):   2-2=0

(3,3):    3-2=1

(4,1):    1-2=-1

finally we have:

(1,0), (3,1) and (4,-1)

7 0
3 years ago
What are the solutions of the inequality (x-3)(x+5)<=0
GarryVolchara [31]

Assuming that the inequality you were going for was a ≤, set both polynomials less than or equal to 0.

x - 3 ≤ 0

x + 5 ≤ 0

For the first equation add 3 to both sides of the inequality. For the second, subtract 5 from both sides.

x ≤ 3

x ≤ - 5

These would be your solutions I guess, however, if you want to expand upon that, your actual answer is (- ∞, - 5] because if you were to plot these two inequalities on a number line, that is where the overlap would occur.

4 0
3 years ago
The following is a linear programming formulation of a labor planning problem. There are four overlapping shifts, and management
dexar [7]

Answer:

d. 15

Step-by-step explanation:

Putting the values in the shift 2 function

X1 + X2 ≥ 15

where x1=  13, and x2=2

13+12≥ 15

15≥ 15

At least 15 workers must be assigned to the shift 2.

The LP model questions require that the constraints are satisfied.

The constraint for the shift 2 is that the  number of workers must be equal or greater than 15

This can be solved using other constraint functions e.g

Putting  X4= 0 in

X1 + X4 ≥ 12

gives

X1 ≥ 12

Now Putting the value X1 ≥ 12  in shift 2 constraint

X1 + X2 ≥ 15

12+ 2≥ 15

14 ≥ 15

this does not satisfy the condition so this is wrong.

Now from

X2 + X3 ≥ 16

Putting X3= 14

X2 + 14 ≥ 16

gives

X2  ≥ 2

Putting these in the shift 2

X1 + X2 ≥ 15

13+2 ≥ 15

15 ≥ 15

Which gives the same result as above.

6 0
3 years ago
Courtney has a total of 88 stamps worth $15.56. Some are $0.25 stamps and some are $0.02 stamps. How many of each foes she have?
olganol [36]

Let x = # of 25-cent stamps

y = # of 2-cent stamps

{   x+ y = 88

{ 0.25x + 0.02y = 15.56

60 25-cent stamps 28 2-cent stamps

5 0
2 years ago
A mother is 13/4 times as tall as her son. Her son is 3 feet tall how tall is the mother.
Kazeer [188]
They’re both really y’all
7 0
3 years ago
Read 2 more answers
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