8 * 2 * 3 = 48 cu in
8 = width
2 = depth
3 = height
Haha, this is more a problem of reading the question right :)
(x^2-4x+4)/(x^2+10x+25) * (x+5)/(x^2+3x-10)
Upon factoring the numerator and denominators...
[(x-2)^2/(x+5)^2]*(x+5)/((x+5)(x-2)) so on the right side the (x+5)s cancel
((x-2)^2/(x+5)^2)*1/(x-2) which is:
[(x-2)^2]/[(x+5)^2*(x-2)] now you can see that (x-2)^1 cancels
(x-2)/(x+5)^2 or if you prefer it expanded...
(x-2)/(x^2+10x+25)
Let
a------------> first number
b------------> second number
we know that
a+b=-7--------> a=-7-b----------> equation 1
a-b=14--------> equation 2
<span>I substitute 1 in 2
</span>
(-7-b)-b=14-------------> -7-b-b=14----------> -7-2b=14-------> 2b=-7-14
2b=-21---------> b=-10.5
a=-7-b-------> a=-7-(-10.5)-----> a=-7+10.5------> a=3.5
the answer is
the two numbers are
a=3.5
and
b=-10.5
Answer:u
hard
Step-by-step explanation: