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Sveta_85 [38]
4 years ago
6

Drag each tile to the correct box. Not all tiles will be used

Mathematics
1 answer:
Illusion [34]4 years ago
4 0

Answer:

\frac{2(vt-d)}{t^2}=a

Step-by-step explanation:

Expression to calculate the displacement 'd' is,

d = vt - \frac{1}{2}at^{2}

By subtracting vt from both the sides of the equation.

d - vt = -\frac{1}{2}at^2

vt - d = \frac{1}{2}at^{2} --------(1)

Multiplying with 2 on both the sides of the equation,

2(vt - d) = at² --------(2)

Dividing by 't²' on both the sides of the equation,

\frac{2(vt-d)}{t^2}=\frac{at^2}{t^2}

\frac{2(vt-d)}{t^2}=a --------(3)

Therefore, expression to calculate the acceleration 'a' will be

\frac{2(vt-d)}{t^2}=a

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<h3>What is coordinate geometry?</h3>

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The point is given as (3, 3.5).

Then name a second point so that the two points form a horizontal segment.

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Let x be the abscissa.

Then the point will be given as (x, 3.5).

More about the coordinate geometry link is given below.

brainly.com/question/1601567

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