Question

Drag each tile to the correct box. Not all tiles will be used

Answer 1

Answer:

$\frac{2(vt-d)}{t^2}=a$

Step-by-step explanation:

Expression to calculate the displacement 'd' is,

d = vt - $\frac{1}{2}at^{2}$

By subtracting vt from both the sides of the equation.

d - vt = -$\frac{1}{2}at^2$

vt - d = $\frac{1}{2}at^{2}$ --------(1)

Multiplying with 2 on both the sides of the equation,

2(vt - d) = at² --------(2)

Dividing by 't²' on both the sides of the equation,

$\frac{2(vt-d)}{t^2}=\frac{at^2}{t^2}$

$\frac{2(vt-d)}{t^2}=a$ --------(3)

Therefore, expression to calculate the acceleration 'a' will be

$\frac{2(vt-d)}{t^2}=a$