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Tpy6a [65]
3 years ago
9

LOTS OF POINTS!! answer 4-6

Mathematics
2 answers:
Mkey [24]3 years ago
6 0

Answer:

4 1x2x3 =6

5 3x4x1=12

6 2x3x2=12

Step-by-step explanation:

riadik2000 [5.3K]3 years ago
4 0

Answer:

Step-by-step explanation:

4 1x2x3 =6

5 3x4x1=12

6 2x3x2=12

Hope that help

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In your own words, explain what a rational expression is and give and example of one.
patriot [66]

Answer:

A rational expression is when the numerator and the denominator are polynomials. An example is  5/x − 2

8 0
3 years ago
PLEASE HELP ASAP<br> Find the missing side lengths.
zimovet [89]
You can see it’s 90

You can also see it because. A triangle is 180 degrees so

45+45=90

180-90=90

So x=90
8 0
2 years ago
Its in the picture below<br><br> a: 1% decay<br> b: 10% decay<br> c: 9% growth<br> d: 90% growth
Trava [24]

Answer:

  b:  10% decay

Step-by-step explanation:

Expressed as a percentage change, the growth is usually the value of the base of the exponential function after 1 has been subtracted. That result is expressed as a percent:

  0.9 - 1 = -0.10 = -10% . . . . . 10% decay

_____

The "t/12" exponent means this is the decay that is experienced over 12 units of time. This might be the annual decay, where t is expressed in months, for example.

6 0
3 years ago
Pls help !!! Thank you
pishuonlain [190]

Answer:

y-10=2/3(x-8)

Step-by-step explanation:

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5 0
3 years ago
The caller times at a customer service center has an exponential distribution with an average of 22 seconds. Find the probabilit
jenyasd209 [6]

Answer:

The probability that a randomly selected call time will be less than 30 seconds is 0.7443.

Step-by-step explanation:

We are given that the caller times at a customer service center has an exponential distribution with an average of 22 seconds.

Let X = caller times at a customer service center

The probability distribution (pdf) of the exponential distribution is given by;

f(x) = \lambda e^{-\lambda x} ; x > 0

Here, \lambda = exponential parameter

Now, the mean of the exponential distribution is given by;

Mean =  \frac{1}{\lambda}  

So,  22=\frac{1}{\lambda}  ⇒ \lambda=\frac{1}{22}

SO, X ~ Exp(\lambda=\frac{1}{22})  

To find the given probability we will use cumulative distribution function (cdf) of the exponential distribution, i.e;

    P(X\leq x) = 1 - e^{-\lambda x}  ; x > 0

Now, the probability that a randomly selected call time will be less than 30 seconds is given by = P(X < 30 seconds)

        P(X < 30)  =  1 - e^{-\frac{1}{22} \times 30}

                         =  1 - 0.2557

                         =  0.7443

7 0
3 years ago
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