Find the missing part. Find Px

Mathematics

1 answer:

MariettaO [177]3 years ago

8 0

Px = missing length
xy = 3
Py = 6
these are the 3 sides of a right triangle; let's use the Pythagorean theorem to find Px
(Px)² + 3² = 6² subtract 3² from both sides
(Px)² = 36 - 9 simplify the right
(Px)² = 27 take the square root of both sides
Px = $\sqrt{27}$
Px = $3 \sqrt{3}$

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The perimeter of a rectangular garden is 4534 m. The length is 1125 m more than thrice the width. Find the length and the width

IrinaVladis [17]

Answer:

length = 1696 m

breadth = 571 m

Step-by-step explanation:

perimeter = 4534 m

let breadth be b

so length = b + 1125 m

perimeter of rectangular garden = 2(l+b)

4534 m = 2(b+1125m+b) {substituting the value}

or, 4534 m = 2(2b+1125m)

or, 4534 m = 4b + 2250 m

or, 4534 m - 2250m = 4b

or, 2284m = 4b

or, b = 2284m/4

so, b = 571m

so, l = b + 1125 m

= 571 m + 1125m

= 1696 m

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3 years ago

I need help its urgent ASAP will mark you the brainliest

kherson [118]

9514 1404 393

Answer:

BE = 266 2/3

PE = 233 1/3

Step-by-step explanation:

Part A: The figure has 3 triangles, all similar. In order of shortest-to-longest side lengths, they are ...

ΔBPE ~ ΔBCG ~ ΔGRE

Part B: They can be declared similar by the AA postulate. For BPE and BCG, the angles at B are vertical angles, so are congruent. The angles at C and G are alternate interior angles, so are congruent.

For triangles BPE and GRE, angle E is congruent to itself, The angles at R and P are corresponding angles, so are congruent.

(Remember, GRPC is a parallelogram, so any line in the figure is a transversal crossing parallel lines.)

Part C:

From parts A and B, we know ΔBPE ~ ΔBCG. Corresponding sides are proportional:

BP/BC = BE/BG = PE/CG

200/300 = BE/400 = PE/350

BE = (400)(2/3) = 266 2/3

PE = (350)(2/3) = 233 1/3

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