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Sergio [31]
3 years ago
15

65000÷9330

Mathematics
1 answer:
Nataly [62]3 years ago
8 0

Step-by-step explanation:

1.answer is 6.9667738478

2 answer is 42.872454448

3answer is 14.1339764202

4answer is 0.0857449089.

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Sabric and Jessica disagree over an inequality statement. Sabric claims that -3.613 > -3.63. Jessica claims that -3.613 <
Pachacha [2.7K]

Answer:

Jessica

Step-by-step explanation:

Jessia is correct

4 0
3 years ago
Read 2 more answers
# 6 The capacity of a cylindrical fuel tank is 2.5 kl and its height 10 m. What is the area of its base?
Lina20 [59]
<h3>The area of base is 0.25 square meter</h3>

<em><u>Solution:</u></em>

Given that,

The capacity of a cylindrical fuel tank is 2.5 kl and its height 10 m

To find: area of base

<em><u>The volume of cylinder is given as:</u></em>

V = \pi r^2h

The area of base of cylinder is area of circle

Area\ of\ circle = \pi r^2

Therefore,

V = base\ area \times height

From given,

h = 10 m

v = 2.5 kl

1 kilo liter = 1 cubic meter

Therefore,

2.5 kl = 2.5 cubic meter

Substitute height = 10 and volume = 2.5

2.5 = base\ area \times 10\\\\ base\ area = \frac{2.5}{10}\\\\ base\ area = 0.25

Thus area of base is 0.25 square meter

5 0
3 years ago
A grocery store received two shipments of watermelon. Each
lys-0071 [83]

Answer:

<u>The degree of overlap between the two distributions is moderate.</u>

Step-by-step explanation:

I got this answer on the test. It is right I promise!

4 0
2 years ago
A zoo has a black rhinoceros that weighs 18 times as much as an average-size chimpanzee. The rhinoceros weighs 2,250 pounds.
Vinvika [58]

Answer: 125 pounds

Step-by-step explanation:

Let's first represent the weight of the black rhinoceros and chimpanzee with variables. We will assign <em>r</em> for the rhinoceros and <em>c</em> for the chimpanzee.

In the question, we were given that the weight for a black rhinoceros is 18 times as much as an average-size chimpanzee. This makes 18 times the chimpanzee's weight equal to the rhinoceros' weight.

Let's put this into an equation.

r=18*c

Now, let's put in the values we know to find the weight of the chimpanzee (i.e., <em>c</em>). We know the weight of a rhinoceros (represented by <em>r</em>) is 2250 pounds, so we can replace it for <em>r</em> in the equation.

2250=18*c

To solve this equation, we can divide both sides by 18 to get c by itself and know what it's value is.

\frac{2250}{18}=\frac{18*c}{18}

We can remove the \frac{18}{18} from the right side to be left with c. We can also divide 2250 by 8 to get the weight of an average-size chimpanzee.

c=\frac{2250}{18}\\ c=125

Hence, an average-size chimpanzee weighs 125 pounds.

8 0
2 years ago
NEED HELP ASP!!!
tino4ka555 [31]

I'm assuming you have the octagonal base flat on the ground/floor. If so, then the horizontal cut through the center would basically cut the prism into two smaller equal pieces. Each piece will have the same octagonal base, but now the height is half as much. The cross section is the same as the base.

One way to picture it is to imagine you had a single room house with a very tall ceiling. Now place a floor between the top and bottom, midway through, so that you divide this house into too stories (each story being the same height). This new floor is a cross section, which is identical to the original floor of the house. Instead of a rectangular floor, picture the floor shape being an octagon.

<h3>Answer: Octagon</h3>
5 0
4 years ago
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