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pychu [463]
3 years ago
5

Springer Products manufactures three different product lines, Model X, Model Y, and Model Z. Considerable market demand exists f

or all models. The following per unit data apply: Model X Model Y Model Z Selling price $52 $60 $74 Direct materials 8 8 8 Direct labor ($16 per hour) 16 16 32 Variable support costs ($5 per machine-hour) 5 10 10 Fixed support costs 12 12 12 If there is excess capacity, which model is the most profitable to produce
Business
1 answer:
Zina [86]3 years ago
5 0

Answer:

Model Y

Explanation:

Calculation for the which model is the most profitable to produce

Using this formula

Most profitable to produce=Selling price-Direct materials-Direct labor-Variable support costs

Let plug in the formula

Model X $52 - $8 - $16- $5 = $23

Model Y $60 - $8- $16 - $10 = $26 Most profitable

Model Z $74- $8 - $33 - $10 = $24

Therefore the model that is the most profitable to produce is MODEL Y because it has the highest amount of $26

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4 years ago
An investment earned the following returns over a four-year period: 28 percent, 21 percent, 1 percent, and -36 percent. What is
riadik2000 [5.3K]

Answer:

A) 0.0618

Explanation:

Variance is given by:

V = \frac{\sum(Xi - \mu)^2}{n}

Where 'Xi' is the value for each term 'i' in the sample of size 'n' and μ is the sample mean.

The mean investment return is:

\mu = \frac{0.28+0.21+0.01-0.36}{4} \\\mu = 0.035

The variance is:

V = \frac{\sum(Xi - \mu)^2}{n}\\V = \frac{(0.28- 0.035)^2+(0.21- 0.035)^2+(0.01- 0.035)^2+(-0.36- 0.035)^2}{4}\\V= 0.0618

The variance of the returns on this investment is A) 0.0618.

4 0
3 years ago
A time standard was set as 0.20 hour per unit based on the 20th unit produced. Assume the task has a 60 percent learning curve.
Sliva [168]

Answer:

40th unit = 0.11 hr

80th unit = 0.06 hr

160th unit = 0.03 hr

Explanation:

Given :

$T_{20} = 0.2$

Learning rate = 60% = 0.6 (r)

Now using the learning curve equation,

$ T_n = T_1(n)^b$

where b is  $b= \frac{\ln r}{\ln 2} = \frac{\ln 0.6}{\ln 2} $  = -0.833

Now

$ T_{20} = T_1(20)^{-0.833}$

$ 0.20 = T_1 (0.0824)$

$T_1$ = 2.5

For 40th unit

$ T_{40} = 2.5(40)^{-0.833}$

      = 0.11 hrs

For 80th unit

$ T_{80} = 2.5(80)^{-0.833}$

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For 160th unit

$ T_{160} = 2.5(160)^{-0.833}$

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6 0
3 years ago
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Answer:

The population would be 1318 million

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Acording to the formula

<h2>Nt =Noe^{T * r}</h2>

Nt = population size in generation t

No =  initial population size.

e= number e

T= number o years

r = rate

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