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ss7ja [257]
3 years ago
10

Does this graph show a function? Explain how you know.

Mathematics
2 answers:
nignag [31]3 years ago
6 0
The graph fails the vertical line

Hope it helps
Bess [88]3 years ago
4 0

Answer:

a. no the graph fails the vertical line test

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A construction worker has a cable that is 8 yards long. He wants to cut it into 9 equal-length pieces. How long will each piece
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I think it would be B. hope this helps!
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When you divide a number by something bigger than 1 whole,does it grow or shrink?
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                                      The number shrinks.
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3 years ago
Which function is the inverse of y=2/3x-6
Dmitry_Shevchenko [17]

Answer:

y = 3(x + 6)/2

Step-by-step explanation:

I'm assuming that you meant   y = (2/3)x - 6.  

If that's correct, start by interchanging x and y, obtaining:

x = (2/3)y - 6

Next, solve for y:  (2/3)y = x + 6.  Multiplying both sides of this equation by (3/2) isolates y, as desired, and results in:

y = 3(x + 6)/2.  This is the inverse of y = (2/3)x - 6.

7 0
4 years ago
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Write m=-3 and (3,-1) in pointe slope form
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6 0
3 years ago
when the polynomial f(x) is divided by (x-2) the remainder is 4, and when it is divided by (x-3) the remainder is 7. Given that
natima [27]

f(x)=(x-2)(x-3)Q(x)+ax+b

Recall the polynomial remainder theorem: the remainder upon dividing a polynomial p(x) by x-c is equal to p(c). This means that f(2)=4 and f(3)=7, which tell us

4=2a+b

7=3a+b

From here we can solve for a,b:

4=2a+b\implies b=4-2a

7=3a+b=3a+(4-2a)\implies a=3\implies b=-2

so that

f(x)=(x-2)(x-3)Q(x)+3x-2

Now,

\dfrac{f(x)}{(x-2)(x-3)}=Q(x)+\dfrac{3x-2}{(x-2)(x-3)}

so the remainder upon dividing f(x) by (x-2)(x-3) is 3x-2.

Next, if f is a cubic function, then Q(x) is a linear polynomial that can be written as Q(x)=cx-d. The coefficient of x^3 in f(x) is 1 (unity), so that expanding f(x) gives us

f(x)=(x-2)(x-3)(cx-d)+3x-2

f(x)=(cx^3-(5c+d)x^2+(6c+5d)x-6d)+3x-2

f(x)=cx^3-(5c+d)x^2+(6c+5d+3)x-(6d+2)

\implies c=1

and we also have that f(1)=1, so that

1=1-(5+d)+(6+5d+3)-(6d+2)

\implies2d=2\implies d=1

so that

Q(x)=x-1

4 0
3 years ago
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