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timofeeve [1]
3 years ago
7

Which is more, 6 inches or 1 foot? 6 inches 1 foot Neither, they are equal ​

Mathematics
2 answers:
kodGreya [7K]3 years ago
6 0
1 foot is more
6 inches is 0.5 feet
finlep [7]3 years ago
6 0

Answer:

1 foot

Step-by-step explanation:

One foot is 12 inches, and 12 inches is greater than 6 inches.

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The lifetime of a machine part has a continuous distribution on the interval​ (0, 50​) with probability density function​ f, whe
Strike441 [17]

Answer:

Probability that the lifetime of the machine part is less than 13 = 0.6782

Step-by-step explanation:

given that f(x)=(10+x)^{-2}

Normalizing the function we get

\int_{0 }^{50}cf(x)dx=1

\int_{0 }^{50}c(10+x)^{-2}dx=1

\therefore a=\frac{1}{\int_{0 }^{50}(10+x)^{-2}dx}

\therefore a=12

P(x< 13)=\int_{0}^{13}12(10+x)^{-2}dx\\\\P(X< 13)=0.6782

4 0
3 years ago
Help please ???i really don't know this one
Andru [333]
What grade are you in
8 0
3 years ago
The mean incubation time of fertilized eggs is 19 days. Suppose the incubation times are approximately normally distributed with
kotykmax [81]

Answer:

Step-by-step explanation:

Since the incubation times are approximately normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = incubation times of fertilized eggs in days

µ = mean incubation time

σ = standard deviation

From the information given,

µ = 19 days

σ = 1 day

a) For the 20th percentile for incubation times, it means that 20% of the incubation times are below or even equal to 19 days(on the left side). We would determine the z score corresponding to 20%(20/100 = 0.2)

Looking at the normal distribution table, the z score corresponding to the probability value is - 0.84

Therefore,

- 0.84 = (x - 19)/1

x = - 0.84 + 19 = 18.16

b) for the incubation times that make up the middle 97​% of fertilized eggs, the probability is 97% that the incubation times lie below and above 19 days. Thus, we would determine 2 z values. From the normal distribution table, the two z values corresponding to 0.97 are

1.89 and - 1.89

For z = 1.89,

1.89 = (x - 19)/1

x = 1.89 + 19 = 20.89 days

For z = - 1.89,

- 1.89 = (x - 19)/1

x = - 1.89 + 19 = 17.11 days

the incubation times that make up the middle 97​% of fertilized eggs are

17.11 days and 20.89 days

6 0
3 years ago
Quick algebra 1 question for 10 points!
bazaltina [42]

denote \: by \: s \: the \: cost \: of \: a \: sweatshirt \\ denote \: by \: t \: the \: cost \: of \: a \: t \: shirt

3t + 7s = 240.5 \\ 6t + 5s = 220

- 6t - 14s =  - 481 \\ 6t + 5s = 220

- 9s = -  261 \\ s =  \frac{ - 261}{ - 9}  = 29 \: dollars

3t + 7(29) = 240.5 \\

3t + 203 = 240.5

3t = 37.5

t = 12.5 dollars

4 0
2 years ago
What percentage of the original activity in the sample remains after 17.5 days? half life calculation
Tju [1.3M]

The percentage of the original activity in the sample remains after 17.5 days is obtained as N(t) / No x 100%.

<h3>What is half life?</h3>

Half-life is the time required for a quantity to reduce to half of its initial value.

The original activity in the sample that remains after 17.5 days is calculated from half life equation as shown below;

N(t) = No(¹/₂)^t/h

where;

  • N(t) is the mass of the substance remaining
  • No is the initial mass of the substance
  • t is time elapsed = 17.5 days
  • h is the half life of the substance

percentage of the original activity in the sample remains after 17.5 days;

= N(t) / No x 100%

Thus, the percentage of the original activity in the sample remains after 17.5 days is obtained as N(t) / No x 100%.

Learn more about half life here: brainly.com/question/2320811

#SPJ4

8 0
2 years ago
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