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timofeeve [1]
3 years ago
7

Which is more, 6 inches or 1 foot? 6 inches 1 foot Neither, they are equal ​

Mathematics
2 answers:
kodGreya [7K]3 years ago
6 0
1 foot is more
6 inches is 0.5 feet
finlep [7]3 years ago
6 0

Answer:

1 foot

Step-by-step explanation:

One foot is 12 inches, and 12 inches is greater than 6 inches.

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The ratio of the lengths of the sides of △ABC is 3:4:6. The perimeter of the triangle whose vertices are the midpoints of the si
zzz [600]

It is 6, 8, 12 , because you know that the perimeter of the smaller triangle is 13, and those are the midpoints of the larger triangle, so it is like half of the larger triangle. So, it happens that 3+4+6 = 13. So 3*2 , 4*2 , 6*2 will be your answer.

4 0
3 years ago
At a cost of $8 per pound, how many ounces of rice flour can be bought for $3.35?
Lady_Fox [76]

Answer:

$41 cents

Step-by-step explanation:

$8 divided by $3.35 equals $0.41 cents

4 0
2 years ago
Guys please help me match these<br><br> Brainliest will go to the right answer
sergij07 [2.7K]

Answer:

Step-by-step explanation:

10 - m = m - 10                  is  one solution

7x + 5 = 7(x + 5)                is  no solution

3(t + 2) = (2 + 3t) + 4         is identity

hope this helps!

mark me brainliest :D

3 0
3 years ago
A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student
yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the difference between population means is:

CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}

The information provided is as follows:

n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43

The critical value of <em>z</em> for 98% confidence level is,

z_{\alpha/2}=z_{0.02/2}=2.326

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}

     =(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0
3 years ago
7,801 + = 4,890 what is the number
zysi [14]
You subtract the numbers 7,801 and 4890

The answer is 2,911
4 0
3 years ago
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