Answer:
A person in a group where 5 people are sharing 3 small bags of snickers
Step-by-step explanation:
Let the number of calories in one bag of snickers =x
Number of calories in 3 small bags of snickers =3x
- If 5 people share 3 small bags of snickers, 1 person's share

Number of calories in 2 small bags of snickers =2x
- If 7 people share 2 small bags of snickers, 1 person's share

We then compare the two.
Let x=1

Therefore, a person in a group where 5 people are sharing 3 small bags of snickers gets more calories.
F(x)=2x^2-x-6
Factoring:
f(x)=2(2x^2-x-6)/2=(2^2x^2-2x-12)/2=[(2x)^2-(2x)-12]/2
f(x)=(2x-4)(2x+3)/2=(2x/2-4/2)(2x+3)→f(x)=(x-2)(2x+3)
g(x)=x^2-4
Factoring
g(x)=[sqrt(x^2)-sqrt(4)][sqrt(x^2)+sqrt(4)]
g(x)=(x-2)(x+2)
f(x)/g(x)=[(x-2)(2x+3)] / [(x-2)(x+2)
Simplifying:
f(x)/g(x)=(2x+3)/(x+2)
Answer: Third Option (2x+3)/(x+2)
Answer:
1) 
2) 
3) 
4) 
5) 
Step-by-step explanation:
According to the information given in the exercise, the value of "x" is:

Then:
1) You must substitute
into the expresion
:

Now, you must evaluate:

2) You have to substitute the given value of "x" into the second expression:

Finally, evaluating, you get the following result:

3) According to the Zero exponent Rule, any non-zero number with an exponent of zero is equal to 1.
Then, substituting
into the expression
and then evaluating, you get:

4) By definition:

Then, substituting
into
and evaluating, you get:

5) Since:

When you substitute the given value of "x" into the last expression and then you evaluate, you get:
