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3 years ago

Anybody know this I don't want to go to summer school I'm being serious pls help

Mathematics

2 answers:

irina1246 [14]3 years ago

5 0

Answer:

the bus is travelling faster

It is travelling faster by 22-18= 4 meters per second

Step-by-step explanation:

if you divid the meters per second you get 22 for the car and 18 for the bus

it's going faster by 4 meters per second\

belka [17]3 years ago

3 0

The bus is traveling faster

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Find the angle between u =the square root of 5i-8j and v =the square root of 5i+j.

fenix001 [56]

Answer:

The angle between vector $\vec{u} = 5\, \vec{i} - 8\, \vec{j}$ and $\vec{v} = 5\, \vec{i} + \, \vec{j}$ is approximately $1.21$ radians, which is equivalent to approximately $69.3^\circ$ .

Step-by-step explanation:

The angle between two vectors can be found from the ratio between:

their dot products, and
the product of their lengths.

To be precise, if $\theta$ denotes the angle between $\vec{u}$ and $\vec{v}$ (assume that $0^\circ \le \theta < 180^\circ$ or equivalently $0 \le \theta < \pi$ ,) then:

$\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|}$ .

<h3>Dot product of the two vectors</h3>

The first component of $\vec{u}$ is $5$ and the first component of $\vec{v}$ is also

The second component of $\vec{u}$ is $(-8)$ while the second component of $\vec{v}$ is $1$ . The product of these two second components is $(-8) \times 1= (-8)$ .

The dot product of $\vec{u}$ and $\vec{v}$ will thus be:

$\begin{aligned} \vec{u} \cdot \vec{v} = 5 \times 5 + (-8) \times1 = 17 \end{aligned}$ .

<h3>Lengths of the two vectors</h3>

Apply the Pythagorean Theorem to both $\vec{u}$ and $\vec{v}$ :

$\| u \| = \sqrt{5^2 + (-8)^2} = \sqrt{89}$ .
$\| v \| = \sqrt{5^2 + 1^2} = \sqrt{26}$ .

<h3>Angle between the two vectors</h3>

Let $\theta$ represent the angle between $\vec{u}$ and $\vec{v}$ . Apply the formula $\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|}$ to find the cosine of this angle:

$\begin{aligned} \cos(\theta)&= \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|} = \frac{17}{\sqrt{89}\cdot \sqrt{26}}\end{aligned}$ .

Since $\theta$ is the angle between two vectors, its value should be between $0\; \rm radians$ and $\pi \; \rm radians$ ( $0^\circ$ and $180^\circ$ .) That is: $0 \le \theta < \pi$ and $0^\circ \le \theta < 180^\circ$ . Apply the arccosine function (the inverse of the cosine function) to find the value of $\theta$ :

$\displaystyle \cos^{-1}\left(\frac{17}{\sqrt{89}\cdot \sqrt{26}}\right) \approx 1.21 \;\rm radians \approx 69.3^\circ$ .

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3 years ago

Write an equation of the line passing theough the point (4,-1) and perpendicular to the line y=2x-5.

Gwar [14]

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3 years ago

Find the value of y- ( 8y +2) and (3y +5)= 73

kiruha [24]

Y=6 because if you break it down you get (11y+7) =73 then you subtract 7 from both sides to get 11y=66 then you divide 11 on both sides to get y=6

7 0

3 years ago

Solve the inequality<br> -2≥4p+6+4

Alchen [17]

Hi there

-2 ≥ 4p + 6 + 4

-2 ≥ 4p + 10

4p +10 ≤ -2

Now subtract 10 form both sides

4p + 10 - 10 ≤ -2 - 10

4p ≤ -12

Divide by 4

4p/4 ≤ -12/4

p ≤ -3

I hope that's help:)

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4 years ago

A school has two computer labs Each lap has 30 computers a total of six computers in the school or not working which expression

Eddi Din [679]

Answer:

Step-by-step explanation:

A school has two computer labs and each lan has 30 computers. This means that the total number of computers is the sum of the number of computers in each lab

Total number of computers = 30+30 = 60

A total of six computers in the school or not working.

The expression that can be used to find the number of working computers in the school will be

Let the number of computers that are working be x

the number of computers that are working is total number of computers minus the number of computers that are not working be

The expression that can be used to find the number of working computers in the school will be

x = 60 - 6

x = 54

6 0

3 years ago