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3 years ago

11

What is meant by conflict cycle?

1 answer:

Radda [10]3 years ago

4 0

Answer:

It all starts with something that creates "Tension" between you and another person. "Tension" leads to "Role Dilemma" or blaming the other person for the tension and the problem. ... Then both of you start "Gathering Injustices" to use as ammunition for the inescapable showdown.

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Type the correct answer in the box. Use numerals instead of words.

Luden [163]

Answer:

Step-by-step explanation:

The answer should be X= -3

3 0

2 years ago

The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further from the lighthouse. The new bearing is 25°

djverab [1.8K]

Answer:

The distance between the ship at N 25°E and the lighthouse would be 7.26 miles.

Step-by-step explanation:

The question is incomplete. The complete question should be

The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further towards the south. The new bearing is N 25°E. What is the distance between the lighthouse and the ship at the new location?

Given the initial bearing of a lighthouse from the ship is N 37° E. So, $\angle ABN$ is 37°. We can see from the diagram that $\angle ABC$ would be $180-37=$ 143°.

Also, the new bearing is N 25°E. So, $\angle BCA$ would be 25°.

Now we can find $\angle BAC$ . As the sum of the internal angle of a triangle is 180°.

$\angle ABC+\angle BCA+\angle BAC=180\\143+25+\angle BAC=180\\\angle BAC=180-143-25\\\angle BAC=12$

Also, it was given that ship sails 2.5 miles from N 37° E to N 25°E. We can see from the diagram that this distance would be our BC.

And let us assume the distance between the lighthouse and the ship at N 25°E is $AC=x$

We can apply the sine rule now.

$\frac{x}{sin(143)}=\frac{2.5}{sin(12)}\\ \\x=\frac{2.5}{sin(12)}\times sin(143)\\\\x=\frac{2.5}{0.207}\times 0.601\\ \\x=7.26\ miles$

So, the distance between the ship at N 25°E and the lighthouse is 7.26 miles.

3 0

3 years ago

Hurry and answer i need a real answer

tekilochka [14]

Answer: A...................................

6 0

3 years ago

What value makes the equation true? 2(x-5)=20

SashulF [63]

2(x-5)=20

Divide both sides by 2 (division of property equality)

x - 5 = 10

Add 5 to both sides (addition of property equality)

x = 15

Answer

x = 15 is the solution

6 0

2 years ago

What are the zeros of f(x) = x2 + x - 20?

jeyben [28]

Answer:

x = - 5, x = 4

Step-by-step explanation:

Given

f(x) = x² + x - 20

To find the zeros equate f(x) to zero, that is

x² + x - 20 = 0

Consider the factors of the constant term ( - 20) which sum to give the coefficient of the x- term ( + 1)

The factors are + 5 and - 4, since

5 × - 4 = - 20 and + 5 - 4 = + 1, hence

(x + 5)x - 4) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 5 = 0 ⇒ x = - 5

x - 4 = 0 ⇒ x = 4

8 0

2 years ago

Read 2 more answers