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2 years ago

Please help!!! Which of the following expand (x + y)^5 using Pascal’s Triangle?

Mathematics

1 answer:

pishuonlain [190]2 years ago

6 0

Answer:

${x}^{5} + 5 {x}^{4} y + 10 {x}^{3} {y}^{2} + 10 {x}^{2} {y}^{3} + 5x {y}^{4} + {y}^{5}$

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A rectangle has an area of 616 m² and a width of 22m. What is its length?

daser333 [38]

Answer:

l=28m

w Width

A Area

616

m²

Using the formula

A=wl

Solving forl

l=A

w=616

22=28m

hope this will help you

make me brainliest

8 0

3 years ago

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Someone please help me I’ll give out brainliest please dont answer if you don’t know

Anika [276]

Answer:

Step-by-step explanation:

5(2) - (2)^3 = 10 - 8 = 2

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3 years ago

Craig has a rectengular deck that measures 799 inches and 245 inches premeter and if the addtional deck is 33 inches longer,what

melomori [17]

Answer:

The length of the lights is 2088 inches

Step-by-step explanation:

The question is mixed up with another (See comment for correct question)

Given

$Length = 799in$

$Width = 245in$

Required

The perimeter of the deck (this is what the question implies)

The perimeter (P) is:

$P = 2 * (Length + Width)$

$P = 2 * (799 + 245)$

$P = 2 * 1044$

$P = 2088$

3 0

3 years ago

Please help. I’ll mark you as brainliest if correct!

chubhunter [2.5K]

Answer:

$\boxed{\sf \ \ \ f^{-1}(x)=1+\sqrt{x} \ \ \ }$

Step-by-step explanation:

the minimum of f is for x = 1 and f(1)=0

f is decreasing for x<=1 and increasing for x>=1

so the domain is $[1;+\infty[$

$f^{-1}(f(x))=x =f^{-1}((x-1)^2)\\\\f(f^{-1}(x))=x=(f^{-1}(x)-1)^2$

x>=1 so x is positive and we can take the square root

so $f^{-1}(x)=1+\sqrt{x}$

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3 years ago

Multiply and simplify. 2/3 * (1/3 + 3 1/4)=?

kondor19780726 [428]

2/3 × (1/3 + 3 1/4)
= 2/3 (1/3 + 13/4)
= 2/3 (43/12)
= 43/18
= 2 7/18

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3 years ago

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