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nika2105 [10]
4 years ago
12

I need help with this one

Mathematics
2 answers:
Rus_ich [418]4 years ago
8 0
I believe the answer would be A. 729 because 9 • -9 = -81 • -9 = 729. (A positive times a negative equals a negative, and a negative times a negative is a positive.)
N76 [4]4 years ago
6 0
The answer is A because 9 x 9 x 9 = 729. The exponent above the 9 means to multiply the base (9) 3 times. 
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Find the possible value or values of n in the quadratic equation 2n2 – 7n + 6 = 0
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2n^2-7n+6=0

2n^2-4n-3n+6=0

2n(n-2)-3(n-2)=0

(2n-3)(n-2)=0

n=3/2, n=2
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a number that can be written as a fraction of two integers is called ___ number. it has decimal presentation that termite or rep
raketka [301]

Answer:

it is called an irrational number

Step-by-step explanation:

I think that this is a fact answer, so I don't know how to explain it

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What value of k in the equation kx+10=6y would give a line with a slope of -3?​
Rama09 [41]

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7 0
4 years ago
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Solve the proportion using cross products.
djyliett [7]

Answer:

  h = 20

Step-by-step explanation:

The idea of a "cross product" is that you eliminate denominators by multiplying each numerator by the denominator on the other side of the equality. This is what it looks like:

  \dfrac{29\,\text{miles}}{58\,\text{hours}}=\dfrac{10\,\text{miles}}{h\,\text{hours}}\ \longrightarrow\ (29\,\text{miles})(h\,\text{hours})=(10\,\text{miles})(58\,\text{hours})

Now, you can divide by the units and the coefficient of h to find ...

  h=\dfrac{10\cdot 58}{29}=20

_____

<em>Comment on cross product</em>

IMO, you need to go into the idea of "cross product" with eyes wide open. The rules of equality require that any operation performed on one side of the equation also be performed on the other side. The notion of "cross product" <em>makes it look like you're doing something different</em> to the two sides of the equation.

In fact, the "cross product" is a shortcut for "multiply both sides of the equation by the product of the denominators." Since each denominator term cancels itself, multiplying by the product of denominators <em>looks like</em> multiplying by the other denominator (and throwing away the denominator you have).

__

<em>Another comment on cross product</em>

The idea of "using cross products" is often suggested wherever one fraction is equal to another. In many cases, that is an extra step that is unnecessary.

If the variable is in the numerator, you need only multiply the equation by its denominator, not both of them. If you multiply by both denominators, you find yourself dividing again by the denominator of the fraction not containing the variable. For example, ...

  h/10 = 58/29

using cross products, this is ...

  29h = 10·58

and we need to divide by the 29 that we just multiplied by.

Instead, we could simply multiply by the denominator of h:

  h/10 = 58/29   ⇒   h = 10·58/29

4 0
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kap26 [50]

Answer:

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Step-by-step explanation:

8 0
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