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3 years ago

[Function Composition] could someone help me with this answers or show work either is fine

Mathematics

1 answer:

Ronch [10]3 years ago

6 0

Answer:

The required answer is 100 .

Step-by-step explanation:

Given function to us is ,

⇒ f(n) = 4n + 2 . And we need to find (f • f) (-3)

So , first let's find f•f , which will be ,

⇒ (f • f) = (4n + 2)(4n + 2)

⇒ (f • f) = 4n ( 4n + 2 ) +2 ( 4n + 2)

⇒ (f • f) = 16n² + 8n + 8n + 4

⇒ (f • f) = 16n² + 16n + 4

====================================

Now we need to find (f • f)(-3) . So on substituting f = (-3) , we have :-

⇒ (f • f)(n) = 16n² + 16n + 4

⇒ (f • f)(-3) = 16*(-3)² + 16*(-3) + 4

⇒ (f • f) (-3) = 16* 9 - 48 + 4

⇒ (f • f)(-3) = 144 - 44

⇒ ( f • f) (-3) = 100

<h3>Hence the value of ( f • f)(-3) is 100 .</h3>

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jane loves animals. She has an equal number of beetles, birds and spiders as pets. Apart from human legs, there is a total of 27

kherson [118]

Answer:

16.875 spiders

Step-by-step explanation:

Given

Let

$B = Beetles$

$C = Birds$

$S = Spiders$

So, we have:

$B = C = S$ --- equal amounts

$6B + 2C + 8S = 270$ --- the legs

Required

The number of spider

Since she has an equal amount of B, C and S;

The expression can be written as:

$6B + 2C + 8S = 270$

$6S + 2S + 8S = 270$

$16S = 270$

Solve for S

$S = \frac{270}{16}$

$S = 16.875$

The result of the solution does not represent real life situation because it it is not possible to have a fraction number of spider

5 0

3 years ago

Quick Quick! 1 minute only please! with answer and solution! NOTE: NO DIAGRAM!

Vedmedyk [2.9K]

Let's say Alice is 4 feet tall and Bob is 6 feet tall. The ratio of their heights is the required Alice:Bob = 2:3. That means Bob is 3/2 = 1.5 times taller than Alice.

6 0

3 years ago

A pack of folders has a length of 5 inches, a width of 12 inches, and a height of 1 inch. The pack of folders will be shipped in

777dan777 [17]

Answer:

A) Each pack of folders has a volume of 60 cubic inches.

B) The box has a volume of about 720 cubic inches

D) If the box help 20 packs of folders, it would have a volume of about 1,200 cubic inches.

Step-by-step explanation:

Verify each statement

A) Each pack of folders has a volume of 60 cubic inches.

The statement is True

Because

The volume of each pack of folders is equal to

$V=(5)(12)(1)=60\ in^{3}$

B) The box has a volume of about 720 cubic inches

The statement is True

Because

The volume of the box is equal to the volume of one pack of folders multiplied by 12

$V=(12)60=720\ in^{3}$

C) If the box held 15 packs of folders, it would have a volume of about 1,200 cubic inches

The statement is False

Because

Applying proportion

$\frac{12}{720}\frac{packs}{in^{3}}=\frac{15}{x}\frac{packs}{in^{3}}\\ \\x=720*15/12\\ \\x=900\ in^{3}$

$900\ in^{3}\neq 1,200\ in^{3}$

D) If the box help 20 packs of folders, it would have a volume of about 1,200 cubic inches.

The statement is True

Because

Applying proportion

$\frac{12}{720}\frac{packs}{in^{3}}=\frac{20}{x}\frac{packs}{in^{3}}\\ \\x=720*20/12\\ \\x=1,200\ in^{3}$

$1,200\ in^{3}= 1,200\ in^{3}$

E) Each pack of folders has a volume of 24 cubic inches.

The statement is False

Because

The volume of each pack of folders is equal to

$V=(5)(12)(1)=60\ in^{3}$

7 0

3 years ago

46 cents is what fraction of a dollar

Vikentia [17]

Since there are a 100 cents in a dollar. the 100 is the denominator.
46/100, reduce; 23/50, can't be reduced any further. so 23/50 is the fraction.

7 0

3 years ago

Read 2 more answers

A semicircle is cut out of a rectangular paperboard 24in long and 18n wide, as shown below. What is the perimeter of the paperbo

svet-max [94.6K]

Answer:

Perimeter of the paperboard that remains after the semicircle is removed = 94.26 in

Step-by-step explanation:

Watch the attached figure of how the semi circle is cut out of the rectangular paperboard.

Length = 24 in

Width = 18 in

Radius of the semi circle = Half of the width of the paperboard = $\frac{18}{2}$ = 9 in

1) Circumference of the semi circle = π*radius

= 3.14*9

= 28.26 in

2) Perimeter of the paperboard that remains after the semicircle is removed

= Top + Left + Bottom + Right Circumference of the semi circle

= 24 + 18 + 24 + 28.26

= 94.26 in

5 0

3 years ago