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lord [1]
3 years ago
15

2x+3=-7 What is the answer?

Mathematics
1 answer:
Mashcka [7]3 years ago
4 0

Hi there! With equations like this we want to get our variable on one side and and our constant on the other.

So with 2x + 3 = -7 you'd subtract the constant 3 from both sides of the equal sign to get 2x = -10, then you'd divide both sides by 2 to get x = -5. If you double check your work by replacing x in the original equation with our answer we'd find that 2(-5) + 3 = -7 is correct.

Hope you find this helpful :)

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7 ∙ 15 can be written as _____.<br> 5(7 + 10)<br> 10(7 + 5)<br> 7(10 + 5)
Bogdan [553]
Both side multiply by one number.
8 0
3 years ago
Read 2 more answers
Tammy has 35 coins nickels and quarters. In all she has $4.15. How many of each kind of coin does she have
sergey [27]

The currency called the U.S dollar can be split into smaller forms or currency value of itself. Examples of these smaller forms are: <u><em>dimes, nickels, pennies, and quarters.</em></u>

Tammy has 23 nickels and 12 quarters.

Let's represent the number of:

Nickels = n

Quarters = q

It is important to note that the value of:

<em>1 nickel = $0.05</em>

<em>1 quarter = $0.25</em>

<em />

Tammy has 35 coins nickels and quarters. This statement can be represented using an algebraic equation below:

n + q = 35

This can be rewritten as :

n = 35 - q

In all, she has $4.15. This statement can be represented using an algebraic equation below:

0.05n + 0.25q = 4.15

We substitute 35 - q for n in the above equation.

0.05(35 - q) + 0.25q = 4.15

1.75 - 0.05q + 0.25q = 4.15

Collect like terms

- 0.05q + 0.25q = 4.15 - 1.75

0.2q = 2.4

Divide both sides by 0.2

0.2q/0.2 = 2.4/0.2

q = 12

Therefore, the number of quarters Tammy has is 12.

Solving for the number of nickels, we have the equation:

n = 35 - q

n = 35 - 12

n = 23

Therefore, the number of nickels Tammy has is 23.

To learn more, visit the link below:

brainly.com/question/13312288

8 0
3 years ago
U<br>Po<br>RU<br>2<br>0<br><br><br>What is this?​
seraphim [82]
I don’t know could you do a picture
6 0
3 years ago
Worth 20 points!! If you answer wrong or something not related to the question I will report you! Thanks :)
KonstantinChe [14]

A

f(x) = 2x + 1

f(3) = 2*3 + 1 = 7

B

g(x) = x^2

g(7) = 7^2

g(7)= 49

C

f(g(x)) = 2(g(x) + 1

f(g(x)) = 2 x^2 + 1

f(g(3) = 2* 3^2 + 1

f(g(3) = 19

D

g(f(x)) = (f(x))^2

g(f(x)) = (2x + 1)^2

g(f(3)) = (2*3 + 1)^2 = (6 + 1)^2 = 49

E

f(g(x)) = 2*g(x) + 1

f(g(x)) = 2*x^2 + 1

f(g(3)) = 2*3^2 + 1

f(g(3)) = 2 * 9 + 1

f(g(3)) = 18 + 1

f(g(3) = 19

F

f(g(x)) = 2(g(x)) + 1

f(g(x)) = 2*x^2 + 1  

4 0
3 years ago
Solve x to the third power = 125/27
tensa zangetsu [6.8K]
The answer is 253 because you have to multipy them
7 0
3 years ago
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