Given:
To find:
Whether f(x) and g(x) are inverse of each other by using that f(g(x)) = x and g(f(x)) = x.
Solution:
We know that, two function are inverse of each other if:
and 
We have,
Now,
![[\because g(x)=\dfrac{8}{x}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20g%28x%29%3D%5Cdfrac%7B8%7D%7Bx%7D%5D)
![[\because f(x)=\dfrac{8}{x}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20f%28x%29%3D%5Cdfrac%7B8%7D%7Bx%7D%5D)
Similarly,
Since, and , therefore, f(x) and g(x) are inverse of each other.
Answer:
B. 88°
Step-by-step explanation:
In a properly drawn circle graph, the central angle is proportional to the size of the number being displayed. Here, 122 of 500 selected football. Since the total angle of a circle is 360°, that fraction is ...
(122/500)×360° = 87.84° ≈ 88°
Answer:
452.16 m³
Step-by-step explanation:
d = 3h = 3×4m = 12 m
r = d/2 = 12m/2 = 6 m
V = Ab×h = π·r²·h
= 3.14×36m²×4m
= 452.16 m³
Answer:
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
Step-by-step explanation:
Given that;
the frequencies of there alternatives are;
Frequency A = 60
Frequency B = 12
Frequency C = 48
Total = 60 + 12 + 48 = 120
Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;
Relative Frequency A = Frequency A / total = 60 / 120 = 0.5
Relative Frequency B = Frequency B / total = 12 / 120 = 0.1
Relative Frequency C = Frequency C / total = 48 / 120 = 0.4
therefore;
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
Answer:
B
Step-by-step explanation:
If you arrange a statistics in order from least to greatest, the middle number is the median.
If there is even number of numbers in a list, let it be n numbers, then we take the average of n/2th and n/2 + 1 th terms.
Here, all of them have 6 numbers, so 6/2 = 3 and 4th, we take average of 3rd and 4th number to find the median.
Since they are arrange in order we check each:
Jon = average of 6 and 7, (6+7)/2 = 6.5
Leroy = average of 6 and 8, (6+8)/2 = 7
Simon = average of 5 and 6, (5+6)/2 = 5.5
Leroy's median is the greatest (7).
