Answer:
Yes, they can be aggregated into a single network address of 88.62.0.0/16
Explanation:
Since they all will be using the same outgoing interface so they can be grouped according to next hop which appears to be the same for all four IP address.
First convert all the network addresses into binary.
DECIMAL BINARY CLASS OF IP
88.62.108.0/21 01011000.00111110.01101100.00000000 Class A
88.62.116.0/21 01011000.00111110.01110100.00000000 Class A
88.62.120.0/21 01011000.00111110.01111000.00000000 Class A
88.62.128.0/21 01011000.00111110.10000000.00000000 class A
Looking at the binary form of the address from left to right it can be observed that all for address are identical in the first two octet, that is up to the 16th digit.
So the new subnet mask will be /16, using any of the four address and the /16 mask will can obtain the new network address
All four address can be summarized as 88.62.0.0/16
def even_checker(lst):
for x in lst:
if x%2==0:
print(x)
l = [1,2,3,4,5,6,7,8,9,10]
even_checker(l)
I wrote my code in python 3.8. I hope this helps.
Answer:
Technician A and Technician B are correct
Explanation:
Based on the information provided within the question it can be said that both Technician A and Technician B are correct. A tap handle's right-angled jaw allows many different taps to be attached for different types of situation to more comfortably and conveniently handle that situation. Such as a T-shaped tap in order to cut a thread in an awkward space as Technician B has stated.
