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serg [7]
2 years ago
5

7 pink flowers, 9 purple flowers, and 5 white flowers. What is the ratio of purple flowers to total flowers?

Mathematics
2 answers:
marusya05 [52]2 years ago
5 0

Answer:

9:21

Step-by-step explanation:

leva [86]2 years ago
3 0

Answer:

9:12

Step-by-step explanation:

There are 9 purple flowers, 7 pink flowers, and 5 white flowers.

If you want the ratio of purple to the total, all you have to do is add the pink and white flowers together.

So the answer would be...

9:12

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suppose you toss a coin 100 times and get 60 heads and 40 Tails based on these results what is the probability that the next fli
8_murik_8 [283]
It is stil half becuase the real probability doesnt change
4 0
3 years ago
What are the domain and range of f(x) = 2x - 41?
Darina [25.2K]

The domain of the function is a (-∞, 0) and the range of the function will be f(x) < 0. Then the correct option is C.

<h3>What are domain and range?</h3>

The domain means all the possible values of x and the range means all the possible values of y.

The function is given below.

f(x) = 2x – 41

Then the domain of the function is a (-∞, 0) and the range of the function will be f(x) < 0.

Then the correct option is C.

More about the domain and range link is given below.

brainly.com/question/12208715

#SPJ1

3 0
2 years ago
How do I do this? I’m so confused
Shtirlitz [24]

I say left because you have a straight line, i goes through 0,0 and every time it goes over 1 and up by 3.

5 0
3 years ago
Solution of y - x &lt; -3
devlian [24]

Answer:

Step-by-step explanation:

The inequality y - x < -3 should be solved for y, as follows:

Add x to both sides, obtaining:

y  <  x - 3

Note that this y  <  x - 3 has the form y = mx + b, which represents a straight line.  In this case the straight line would be y = x - 3, meaning that the slope of this line is 1 and the y-intercept is -3.

Because y  <  x - 3  involves the inequality symbol <, draw a dashed line, not a solid line.   The solution set consists of all points on the graph BELOW this dashed line y  <  x - 3.

8 0
3 years ago
1. Express <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bx%282x%2B3%29%20%7D" id="TexFormula1" title="\frac{1}{x(2x+3) }" a
katovenus [111]

1. Let a and b be coefficients such that

\dfrac1{x(2x+3)} = \dfrac ax + \dfrac b{2x+3}

Combining the fractions on the right gives

\dfrac1{x(2x+3)} = \dfrac{a(2x+3) + bx}{x(2x+3)}

\implies 1 = (2a+b)x + 3a

\implies \begin{cases}3a=1 \\ 2a+b=0\end{cases} \implies a=\dfrac13, b = -\dfrac23

so that

\dfrac1{x(2x+3)} = \boxed{\dfrac13 \left(\dfrac1x - \dfrac2{2x+3}\right)}

2. a. The given ODE is separable as

x(2x+3) \dfrac{dy}dx} = y \implies \dfrac{dy}y = \dfrac{dx}{x(2x+3)}

Using the result of part (1), integrating both sides gives

\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3|\right) + C

Given that y = 1 when x = 1, we find

\ln|1| = \dfrac13 \left(\ln|1| - \ln|5|\right) + C \implies C = \dfrac13\ln(5)

so the particular solution to the ODE is

\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3|\right) + \dfrac13\ln(5)

We can solve this explicitly for y :

\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3| + \ln(5)\right)

\ln|y| = \dfrac13 \ln\left|\dfrac{5x}{2x+3}\right|

\ln|y| = \ln\left|\sqrt[3]{\dfrac{5x}{2x+3}}\right|

\boxed{y = \sqrt[3]{\dfrac{5x}{2x+3}}}

2. b. When x = 9, we get

y = \sqrt[3]{\dfrac{45}{21}} = \sqrt[3]{\dfrac{15}7} \approx \boxed{1.29}

8 0
2 years ago
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