All categories

2 years ago

. How many solutions does this system of equations have? y = 4x - 2. y = 4x +5 *

Mathematics

1 answer:

defon2 years ago

3 0

Answer:

No solutions

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

You might be interested in

I need help with only B pls

Marina CMI [18]

Answer:

The population is increasing

Step-by-step explanation:

You can tell that function is increasing from the equation because the rate of change is $\frac{5}{4} = 1.25$

Since this value is greater than $1$ it indicates that the population is being increased.

plz mark me brainliest. :)

4 0

3 years ago

In a city, 6th and 7th Avenues are parallel and the corner that The Pizza Palace is on is a 54° angle. What is the measure of th

tatuchka [14]

In a city, 6th and 7th Avenues are parallel and the corner that The Pizza Palace is on is a 54° angle. What is the measure of the angle that is made with 7th Ave and Broadway on the corner of The Shake Hut?
126°

3 0

3 years ago

Read 2 more answers

The resulting figure after undergoing a transformation

vaieri [72.5K]

Answer:

New being?

Step-by-step explanation:

3 0

3 years ago

What is the solution of the system of equations graphed?

DochEvi [55]

Answer:

A) (-3, 5)

General Formulas and Concepts:

Algebra I

Solving systems of equations by graphing

Step-by-step explanation:

The solution set to any systems of equations is where the 2 lines intersect. According to the graph, we see that the 2 lines intersect at (-3, 5). Therefore, our answer is A.

3 0

3 years ago

Read 2 more answers

A circle has the equation 2x²+12x+2y²−16y−150=0.

KonstantinChe [14]

Answer: B. The coordinates of the center are (-3,4), and the length of the radius is 10 units.

Step-by-step explanation:

The equation of a circle in the center-radius form is:

$(x-h)^{2} +(y-k)^{2}=r^{2}$ (1)

Where $(h,k)$ are the coordinates of the center and $r$ is the radius.

Now, we are given the equation of this circle as follows:

$2x^{2}+12x+2y^{2}-16y-150=0$ (2)

And we have to write it in the format of equation (1). So, let's begin by applying common factor 2 in the left side of the equation:

$2(x^{2}+6x+y^{2}-8y-75)=0$ (3)

Rearranging the equation:

$x^{2}+6x+y^{2}-8y=75$ (4)

$(x^{2}+6x)+(y^{2}-8y)=75$ (5)

Now we have to complete the square in both parenthesis, in order to have a perfect square trinomial in the form of $(a\pm b)^{2}=a^{2}\pm+2ab+b^{2}$ :