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vaieri [72.5K]
3 years ago
12

Solve the system of equations using any method. HELP ME PLEASEEEEE!!!!!!

Mathematics
1 answer:
almond37 [142]3 years ago
7 0

The answer is D, (1/3, 4).

Hope this helped!


You might be interested in
Need help on my qyiz​
Evgesh-ka [11]
H is equal to 8
M is equal to 15.3

20-12= 8
9+6.3= 15.3

Hope this helped
4 0
3 years ago
Multiply and Divide Whole Numbers explain what to do and how to do it
rodikova [14]
Multiplication is a simple way of adding
For example 6x8 is the same as 8+8+8+8+8+8

Any number multiplied by 1 is itself E.g 4x1 = 4

Multiplying by 2 is just doubling

Multiplying by 10 is adding a 0 to the original number

If it is a big number that you do not know how to multiply mentally split it up
E.g 17x13
Split 13 into 10 and 3
17x10= 170
17x3= 51
Then add these numbers
221

If you ever get stuck, use the long method, add them instead, you will get to the right answer but it will take longer

Dividing is not as simple
Like multiplication dividing by one will leave you with the same answer

Dividing by two means you half the number, which may give you a decimal

Bigger numbers are trickier, and you may be allowed to use a calculator for numbers
Below are a number of links, these websites will teach you how to improve your multiplication and division skills:

http://www.bbc.co.uk/schools/gcsebitesize/maths/number/decimalsrev3.shtml

https://m.youtube.com/watch?v=XiXeu9FxAcQ

https://www.tutorialspoint.com/multiply_and_divide_whole_numbers/multiplication_as_repeated_addition.htm


8 0
3 years ago
Read 2 more answers
How to do question 1?Had no idea how to do both parts
givi [52]
y=\dfrac{\ln x}{3x-6}

Differentiate both sides with respect to x:

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{3x-6}x-3\ln x}{(3x-6)^2}

When x=1, you have

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{3-6}1-3\ln1}{(3-6)^2}=\dfrac{-3}9=-\dfrac13

For part (b), we now assume that x and y are functions of an independent variable, which we'll call t (for time). Now differentiating both sides with respect to t, we have

\dfrac{\mathrm dy}{\mathrm dt}=\dfrac{\frac{3x-6}x-3\ln x}{(3x-6)^2}\dfrac{\mathrm dx}{\mathrm dt}

where the chain rule is used on the right side. We're told that y is decreasing at a constant rate of 0.1 units/second, which translates to \dfrac{\mathrm dy}{\mathrm dt}=-0.1. So when x=1, you have

-0.1=\dfrac{\frac{3-6}1-3\ln1}{(3-6)^2}\dfrac{\mathrm dx}{\mathrm dt}
-0.1=-\dfrac13\dfrac{\mathrm dx}{\mathrm dt}
\dfrac{\mathrm dx}{\mathrm dt}=0.3

where the unit is again units/second.
6 0
3 years ago
Use the rules of exponents to evaluate or simplify. Write without negative exponents 8-squr3 is the conjugate of 8+squar 3
NISA [10]
8 - sqrt(3) is indeed the conjugate of 8 + sqrt(3).

What are you asking here?  You are to "evaluate or simplify" what?
5 0
4 years ago
Estimate. Then find the difference.<br><br> 324-285=
mafiozo [28]
            If rounding to the hundreds
To estimate round 324 and 285 to the closest hundred.
300 - 300
Then subtract 300 - 300 =
0
               If rounding to the tens
To estimate round 324 and 285 to the nearest ten.
320 - 290 
Then subtract 320 - 290 =
30
7 0
3 years ago
Read 2 more answers
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