Answer:8^1/6*2^x=32^1/2
We move all terms to the left:
8^1/6*2^x-(32^1/2)=0
Domain of the equation: 6*2^x!=0
x!=0/1
x!=0
x∈R
We get rid of parentheses
8^1/6*2^x-32^1/2=0
We calculate fractions
There is no solution for this equation
Answer:
I beliEve it is D
Step-by-step explanation:
Answer: <u>The 2 roads are 1.25 miles apart.</u>
Step-by-step explanation:
If 1 inch equals .25 miles, then you need to multiply .25 by 5.
Use proportions. Make sure the miles are on the same "side" of the fraction. Side meaning the top or the bottom

1 times X equals 1x
.25 times 5 equals 1.25
1.25 divided by 1 equals 1.25.
x = 5 is not an extraneous solution of the equation.
✓(2x + 6) - ✓(x - 1) = 2
✓(2x + 6) = 2 + ✓(x - 1)
Squaring both the sides of equation, we get
(✓(2x + 6))² = (2 + ✓(x - 1))²
2x + 6 = (2)² + (✓(x - 1))² + 2(2)(✓(x - 1))
2x + 6 = 4 + x - 1 + 4(✓(x - 1))
x + 3 = 4✓(x - 1)
Squaring again on both the side of the equation, we get
(x + 3)² = (4✓(x - 1))²
x² + 3² + 2×3×x = 16(x - 1)
x² + 9 + 6x = 16x - 16
x² - 10x + 25 = 0
By applying middle term splitting on equation (1), we get
x² - 5x - 5x + 25 = 0
x(x - 5) -5(x - 5) = 0
(x - 5) (x - 5) = 0
x = 5 and 5.
Check for extraneous solutions by putting value of x in original equation -
✓(2×5 + 6) - ✓(5 - 1) = 2
✓16 - ✓4 = 2
4 - 2 = 2
2 = 2
LHS = RHS
x = 5 is not an extraneous solution of the equation.
Know more about roots of equation -
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Answer:
she worked 50.5 hours last week.
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Step-by-step explanation: