The function values for the function f(x) = 3x² + 2x - 6, for the values are:
a. f(0) = -6
b. f(2) = 10
c. f(-4) = 34
d. f(b) = 3b² + 2b - 6
e. f(4a) = 48a² + 8a - 6
<h3>How are function values calculated?</h3>
To calculate function value f(k) for a function f(x), we substitute variable x = k, in the function f(x).
<h3>How to solve the question?</h3>
In the question, we are asked to find the function value for the function f(x) = 3x² + 2x - 6 for:
a. f(0)
b. f(2)
c. f(-4)
d. f(b)
e. f(4a).
We calculate these in the following ways:-
a. f(0):
We substitute the value of x = 0 in the function f(x).
Therefore f(0) = 3(0)² + 2(0) - 6,
or, f(0) = 0 + 0 - 6 = -6.
Therefore, the function value f(0) for the function f(x) = 3x² + 2x - 6 is <u>-6</u>.
b. f(2):
We substitute the value of x = 2 in the function f(x).
Therefore f(2) = 3(2)² + 2(2) - 6,
or, f(2) = 12 + 4 - 6 = 10.
Therefore, the function value f(2) for the function f(x) = 3x² + 2x - 6 is <u>10</u>.
c. f(-4):
We substitute the value of x = -4 in the function f(x).
Therefore f(-4) = 3(-4)² + 2(-4) - 6,
or, f(-4) = 48 - 8 - 6 = 34.
Therefore, the function value f(-4) for the function f(x) = 3x² + 2x - 6 is <u>34</u>.
d. f(b):
We substitute the value of x = b in the function f(x).
Therefore f(b) = 3(b)² + 2(b) - 6,
or, f(b) = 3b² + 2b - 6.
Therefore, the function value f(b) for the function f(x) = 3x² + 2x - 6 is <u>3b² + 2b - 6</u>.
e. f(4a):
We substitute the value of x = 4a in the function f(x).
Therefore f(4a) = 3(4a)² + 2(4a) - 6,
or, f(0) = 48a² + 8a - 6.
Therefore, the function value f(0) for the function f(x) = 3x² + 2x - 6 is <u>48a² + 8a - 6</u>.
Learn more about finding function values at
brainly.com/question/27943419
#SPJ2
![y= \sqrt[5]{Bx+C}](https://tex.z-dn.net/?f=y%3D%20%5Csqrt%5B5%5D%7BBx%2BC%7D%20)
</span>