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Fynjy0 [20]
3 years ago
5

A car that cost 700,000.00 depreciates 15% in the value each year for the first five years. What is the cost after 5 years?

Mathematics
1 answer:
Setler79 [48]3 years ago
5 0

Answer:

310559.29375

Step-by-step explanation:

i multiplied the original 700,000 times 0.15 to see what that would equal which was 105,000 then took that away from 700k which was 595,000 then multiplied that by 0.15 which was 89,250 i did this process 5 times and came up with 310,559. 29375

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3x^2 - 4x = -2<br> Solve
amid [387]

Answer:

x =   \bigg \{\frac{ 2   - \sqrt{2} \: i }{3}, \:  \: \frac{ 2    +  \sqrt{2} \: i }{3} \bigg \}

Step-by-step explanation:

3 {x}^{2}  - 4x =  - 2 \\ 3 {x}^{2}  - 4x + 2 = 0 \\ equating \: it \: with  \\ a {x}^{2}  + bx + c = 0 \\ a = 3 \:  \: b =  - 4 \:  \: c = 2 \\  {b}^{2}  - 4ac \\  =  {( - 4)}^{2}  - 4 \times 3 \times 2 \\  = 16 - 24 \\  =  - 8  \\  \ {b}^{2}  - 4ac < 0  \\  \therefore \: given \: quadratic \: equation \: have \:  \\ imaginary \: solutios. \\  \\ x =  \frac{ - b \pm \sqrt{{b}^{2}  - 4ac } }{2a}  \\ =  \frac{ - ( - 4) \pm \sqrt{ - 8} }{2 \times 3} \\ =  \frac{ 4 \pm 2\sqrt{2} \: i }{2 \times 3}  \\  =  \frac{ 2 \pm \sqrt{2} \: i }{3} \\  \therefore \: x  = \frac{ 2   - \sqrt{2} \: i }{3}  \: or \: x  = \frac{ 2   +  \sqrt{2} \: i }{3} \:  \\  \\ x =   \bigg \{\frac{ 2   - \sqrt{2} \: i }{3}, \:  \: \frac{ 2    +  \sqrt{2} \: i }{3} \bigg \}

7 0
3 years ago
Find the slope of the line that contains the points (4,20) and (6,-4)
Y_Kistochka [10]
Slope = (y2-y1) / (x2-x1)
= (-4-20) / (6-4)
= (-24) / (2)
= (-12)

The slope of the line is (-12)
4 0
2 years ago
The diagram compares the ratio of girls in the chorus to boys in the chorus what is the ratio of girls to boys if there are 40 s
Gala2k [10]
Ratio of girls to boys is 3:2....added = 5.....this means that 3/5 of the total students are girls and 2/5 of the total students are boys.

so if there are 50 students...
3/5(50) = 150/5 = 30 girls
2/5(50) = 100/5 = 20 boys
7 0
2 years ago
It's easy I'm just not I'm my head rn can someone help?
marta [7]
B and C for sure maybe A. Def not D
8 0
3 years ago
RRS-1
AVprozaik [17]

The missing measures are listed below:

  1. m \angle 1 = m \angle 3 = m \angle 6 = 59^{\circ}
  2. m\angle 2 = m\angle 4 = m\angle 5 = m \angle 11 = 31^{\circ}
  3. m\angle 7 = m\angle 8 = m\angle 9 = m\angle 10 = 118^{\circ}

<h3>Procedure - Finding missing angles in a quadrilateral</h3>

In this question we must determine the measures of the <em>missing</em> angles by both <em>geometric</em> and <em>algebraic</em> means, whose procedure is presented below:

  1. x = 59^{\circ} Given
  2. m \angle 3 = 59^{\circ} Alternate internal angles
  3. m \angle 11 = 31^{\circ} Complementary angles
  4. m \angle 4 = 31^{\circ} Alternate internal angles
  5. m \angle 6 = 59^{\circ} Isosceles triangle
  6. m \angle 9 = 62^{\circ} Sum of internal angles in a triangle
  7. m \angle 10 = 118^{\circ} Supplementary angles
  8. m \angle 8 = 62^{\circ}, m\angle 7 = 118^{\circ} Vertical angles
  9. m \angle 2 = 31^{\circ} Sum of internal angles in a triangle
  10. m \angle 5 = 31^{\circ} Sum of internal angles in a triangle
  11. m \angle 1 = 59^{\circ} Sum of internal angles in a triangle/Result

The missing measures are listed below:

  1. m \angle 1 = m \angle 3 = m \angle 6 = 59^{\circ}
  2. m\angle 2 = m\angle 4 = m\angle 5 = m \angle 11 = 31^{\circ}
  3. m\angle 7 = m\angle 8 = m\angle 9 = m\angle 10 = 118^{\circ}

To learn more on angles, we kindly invite to check this verified question: brainly.com/question/15767203

5 0
2 years ago
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