Question

Find the perimeter of the triangle to the nearest unit with vertices A(-2,4) B(-2,-2) and C(4,-2) ​

Answer 1

Answer:

20

Step-by-step explanation:

Use the distance equation to find the length of each side:

d = √((x₂ − x₁)² + (y₂ − y₁)²)

where (x₁, y₁) and (x₂, y₂) are the points (the order doesn't matter).

AB:

d = √((-2 − (-2))² + (-2 − 4)²)

d = 6

BC:

d = √((4 − (-2))² + (-2 − (-2))²)

d = 6

AC:

d = √((-2 − 4)² + (4 − (-2))²)

d = 6√2

So the perimeter is:

AB + BC + AC

6 + 6 + 6√2

≈ 20