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Hoochie [10]
3 years ago
7

Find the perimeter of the triangle to the nearest unit with vertices A(-2,4) B(-2,-2) and C(4,-2) ​

Mathematics
1 answer:
astraxan [27]3 years ago
8 0

Answer:

20

Step-by-step explanation:

Use the distance equation to find the length of each side:

d = √((x₂ − x₁)² + (y₂ − y₁)²)

where (x₁, y₁) and (x₂, y₂) are the points (the order doesn't matter).

AB:

d = √((-2 − (-2))² + (-2 − 4)²)

d = 6

BC:

d = √((4 − (-2))² + (-2 − (-2))²)

d = 6

AC:

d = √((-2 − 4)² + (4 − (-2))²)

d = 6√2

So the perimeter is:

AB + BC + AC

6 + 6 + 6√2

≈ 20

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X varies directly as y. If x is 9 when y is 4, find x when-y is 8.
jeka94

Answer:

see explanation

Step-by-step explanation:

Given x varies directly as y then the equation relating them is

x = ky ← k is the constant of variation

To find k use the condition x = 9 when y = 4

k = \frac{x}{y} = \frac{9}{4} = 2.25

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When y = 8, then

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3 years ago
I NEED HELP PLEASE HELP. SHOW ME HOW YOU DID IT
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Sin = - 4/8

Quadrant IV = only cosine is positive

a = height (4)
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b = 6.93 @
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cos =
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tan = - 4/
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