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3 years ago

Find the perimeter of the triangle to the nearest unit with vertices A(-2,4) B(-2,-2) and C(4,-2)

Mathematics

1 answer:

astraxan [27]3 years ago

8 0

Answer:

Step-by-step explanation:

Use the distance equation to find the length of each side:

d = √((x₂ − x₁)² + (y₂ − y₁)²)

where (x₁, y₁) and (x₂, y₂) are the points (the order doesn't matter).

AB:

d = √((-2 − (-2))² + (-2 − 4)²)

d = 6

BC:

d = √((4 − (-2))² + (-2 − (-2))²)

d = 6

AC:

d = √((-2 − 4)² + (4 − (-2))²)

d = 6√2

So the perimeter is:

AB + BC + AC

6 + 6 + 6√2

≈ 20

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Please explain this step by step and solve within 10-20 minutes please

DaniilM [7]

Answer:

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Step-by-step explanation:

Given:

y varies directly with x .

Also x = 7 when y = 18

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y = ? when x = 17

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y varies directly with x .

i.e. y is directly proportional to x

∴ $y = k\times x$

Where

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First we will find constant of proportionality k,

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3 years ago

Find the perimeter of the triangle to the nearest unit with vertices A(-2,4) B(-2,-2) and C(4,-2) ​

Find the perimeter of the triangle to the nearest unit with vertices A(-2,4) B(-2,-2) and C(4,-2)