3 years ago

The intercepts of the equation x^2 + 4y^2 = 16 are ___ PLEASE HELP

1 answer:

3 0

Yintercepts are where x=0
set to zero to solve

0^2+4y^2=16
4y^2=16
divide 4
y^2=4
sqrt both sides
y=+/-2

xintercept is where y=0

x^2+4(0)^2=16
x^2+0=16
x^2=16
sdqrtboth sides
x=+/-4

yintercepts are (0,2) and (0,-2)
xintercepts are (4,0) and (-4,0)

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Answer:

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Step-by-step explanation:

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