Answer:

Step-by-step explanation:
Given:
'w' represents inches of water left after 't' minutes of time.
The dripping out of water is a linear function.
At time 't' equal to 0, the bucket was empty.
After 14 minutes, there are 7 inches of water in the bucket.
A linear function model is of the form: 

Now, at 
At 
Therefore, plugging these values in the above linear model and solving the system of linear equations. This gives,

Therefore, the values of 'm' and 'b' are 0.5 and 0 respectively.
Thus, the linear model is given as:
