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pogonyaev
3 years ago
12

Which table shows ordered pairs that satisfy the function y=x^2+1

Mathematics
1 answer:
ohaa [14]3 years ago
3 0

Where is the table? You could potentiallysolve this by deconstructing the function.

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What is the Triangle Congruence Theorem and is it congruent?
faust18 [17]

Answer:

Two triangles are congruent if their corresponding sides are equal in length and their corresponding interior angles are equal in measure. We use the symbol ≅ to show congruence. Corresponding sides and angles mean that the side on one triangle and the side on the other triangle, in the same position, match.Step-by-step explanation:

5 0
3 years ago
Find the distance between the following coordinates: I(-a,b), J(a,b)
olchik [2.2K]

Answer:

2a

Step-by-step explanation:

using distance formula:

√(x₂-x₁)² + (y₂-y₁)²

putting values,

√{a-(a)}² + {b-b}² = √ {a+a}² + 0²

= √(2a)² = √4a² = 2a

Hope this helps:)

8 0
3 years ago
A coin is tossed and a single 6 sided number cube is rolled. Find the probability of landing on the heads side of the coin and r
Delicious77 [7]

Answer:

The probability of landing on the heads side of the coin and rolling 3 on the number cube is 0.083.

Step-by-step explanation:

Given:

Coin is tossed and a single 6 sided number cube is rolled.

Let the event of tossing head be 'H' and event of rolling a 3 be 'R3'.

Now, we know that:

Probability of an event 'A' = Favorable outcomes of 'A' ÷ Total possible outcomes

Now, for tossing a coin, the total possible outcomes are head and tail. So, there are 2 possible outcomes.

So, probability of event 'H' is given as:

P(H)=\dfrac{n(H)}{n(S)}\\\\P(H)=\frac{1}{2}=0.5

Similarly, for rolling a 6 sided cube, the possible outcomes are numbers 1 to 6. So, the number of possible outcomes is, n(S)=6

Now, probability of rolling a 3 is given as:

P(R3)=\frac{n(R3)}{n(S)}\\\\P(R3)=\frac{1}{6}

Now, both the events 'H' and 'R3' occur together. So, the combined probability is the product of two individual probabilities as they are independent events. So,

P(H\ and\ R3)=P(H)\times P(R3)\\\\P(H\ and\ R3)=\frac{1}{2}\times \frac{1}{6}\\\\P(H\ and\ R3)=\frac{1}{12}=0.083

Note: Independent events are those events whose intersection is an empty set of events or the outcome of one event doesn't affect the outcome of the other event.

Therefore, the probability of landing on the heads side of the coin and rolling 3 on the number cube is 0.083.

4 0
3 years ago
12351 rounded to the nearest hundred explain how you rounded
Nataly_w [17]
\bf 12,\underline{351}\impliedby \textit{3 hundreds, and 51 units, let's round that}
\\\\\\
\begin{array}{llll}
300----- 50-----400\\
\qquad \qquad \uparrow\qquad \qquad \qquad \uparrow  \\

\begin{array}{llll}
anything\ here\\
rounds\ up\ to\\
300
\end{array}\quad
\begin{array}{llll}
anything\ here\\
rounds\ up\ to\\
400
\end{array}
\end{array}
\\\\\\
\textit{therefore, the hundreds value of 300, the 51 tips it over to 400}
\\\\\\
12,\underline{400}
3 0
3 years ago
Read 2 more answers
The values 10 and 15 are plotted on the number line
Brums [2.3K]

im pretty sure the answer is 0.7

4 0
3 years ago
Read 2 more answers
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